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Ta có : 2004 *2005 + (2004*2)+6 và 2004*2005 +2005+2009=2004*2005 + 2014 và 2004*2005+2014
Vậy 2004*2007+6=2005*2005+2009
2004x2007+6
2005x2005 +2009
2004x(2005+2)+6
(2004+1)x2005+2009
2004x2005+4008+6
2004x2005+2005+2009
2004x2005+4014
2004+2005+4014
1
\(\frac{637\times527-189}{637\times526+448}\)
\(=\frac{637\times526+637-189}{637\times526+448}\)
\(=\frac{637\times526+448}{637\times526+448}\)
\(=1\)
\(\frac{2005\times2006+6}{2005\times2005+2011}\)
\(=\frac{2005\times2005+2005+6}{2005\times2005+2011}\)
\(=\frac{2005\times2005+2011}{2005\times2005+2011}\)
\(=1\)
\(A=\frac{2004x2006+10}{2005x2005+9}=\frac{2004x2005+2004+10}{2004x2005+2005+9}=\frac{2004x2005+2014}{2004x2005+2014}=1\)
Ta có: \(\frac{2004\cdot2007+6}{2005\cdot2005+2009}=\frac{\left(2005-1\right)\cdot2007+6}{2005\cdot2005+2009}=\frac{2005\cdot2007-1\cdot2007+6}{2005\cdot2005+2009}=\frac{2005\cdot2007-2007+6}{2005\cdot2005+2009}\)
\(=\frac{\text{2005 x (2005 + 2) - 2007 + 6}}{\text{2005 x 2005 + 2009}}=\frac{\text{2005 x 2005 + 2005 x 2 - 2007 + 6}}{\text{2005 x 2005 + 2009}}=\frac{\text{2005 x 2005 + 4010 - 2007 + 6}}{\text{2005 x 2005 + 2009}}=\text{ }\frac{\text{2005 x 2005 + 2009}}{\text{2005 x 2005 + 2009}}=1\)
2007/2008<1
2008/2009<1
2009/2010<1
2010<2011<1
=>2007/2008+2008/2009+2009/2010+2010/2011<1+1+1+1
=>2007/2008+2008/2009+2009/2010+2010/2011<4(điều cần chứng minh)
2007/2008 < 1
2008/2009 < 1
2009/2010 < 1
2010/2011 < 1
=> 2007/2008 + 2008/2009 + 2009/2010 + 2010/2011 < 1 + 1 + 1 + 1
=>2007/2008 + 2008/2009 + 2009/2010 + 2010/2011 < 4 ( điều cần chứng minh )
ai tk mình mình tk lại cho