tìm x trong các tỉ lệ thức sau :

\(a. \frac{x+5}{x+9}=\frac{x+4}{x+3}\)

\(b. \frac{2x-7}{2x+11}=\frac{5-3x}{4-2x}\)

\(c. \frac{3x+5}{-3x+11}=\frac{7x-5}{7-7x}\)

\(d. \frac{5x-3}{x+1}=\frac{5x-7}{x-1}\)

1) \(\frac{24}{-12}=\frac{x}{5}=\frac{-y}{3}\)Tìm x và y

2) \(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-5}{25}\le\frac{x}{10}< \frac{-3}{4}+\frac{4}{14}+\frac{-2}{8}+\frac{-3}{5}+\frac{5}{7}\)Tìm x

3) \(\frac{8.x+18}{2.x+6}\)Tìm x

1. x+35=17-x
2. 2x-23=-x-2
3. 3x-11=33+5x
4. 13-(2x+5)=21+(22-x)
5. (2x-9)-62=-5x+6
6. 15+(-x+7)=-46-(-2x+7)
7. x+30%x=-1,3
8. x-25%x=\(\frac{1}{2}\)
9. \(\frac{2}{3}\)x+\(\frac{1}{2}x=\frac{5}{2}\)
10. \(\frac{2}{3}x=\frac{5}{12}+\frac{1}{2}x\)

1.

a) \(\text{(3x-5)6=(3x-5)4}\)

2.

a)\(\frac{2}{7}.\frac{2012}{2011}-\frac{2}{2011}.\frac{1}{7}_{ }+\frac{4}{7}\)

b) \(\left(\frac{3}{1.8}+\frac{3}{8.15}+\frac{3}{15.22}+...+\frac{3}{106.113}\right)-\left(\frac{25}{50,55}\frac{25}{55.60}\frac{25}{60.65}...\frac{25}{95.100}\right)\)

ai nhanh đúng mk tk

Find x, know:

\(a,\frac{5}{7}.\frac{3x-8}{5}=\frac{35}{9}\)

\(b,\frac{2}{9}.\frac{5x+1}{2}-\frac{1}{18}=\frac{5}{36}\)

\(\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{2}\)

\(75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2\)

\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}\)

\(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)

\(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)

\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

\(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)