\(\frac{9x-13}{16}=\frac{7y-11}{19}=\frac{z-5}{3}\)

\(\frac{\left(9x-13\right)\cdot\frac{5}{9}}{16\cdot\frac{5}{9}}=\frac{7y-11}{19}=\frac{3\left(z-5\right)}{3\cdot3}\)

\(\frac{5x-\frac{65}{9}}{\frac{80}{9}}=\frac{7y-11}{19}=\frac{3z-15}{9}\)

Áp dụng tc dãy tỉ số bằng nhau, ta được:

\(\frac{5x-\frac{65}{9}}{\frac{80}{9}}=\frac{7y-11}{19}=\frac{3z-15}{9}=\frac{5x-\frac{65}{9}-7y+11+3z-15}{\frac{80}{9}-19+9}=\frac{\left(5x-7y+3z\right)-\left(\frac{65}{9}-11-15\right)}{\frac{80}{9}-\frac{171}{9}+\frac{81}{9}}\)

\(=\frac{9-\left(\frac{65}{9}-\frac{99}{9}-\frac{135}{9}\right)}{-\frac{10}{9}}=\frac{9+\frac{169}{9}}{-\frac{10}{9}}=-\frac{88}{9}:-\frac{10}{9}=\frac{44}{5}\)

=>x=[(44/5*16)+13]/9=769/45

=>y=[(44/5*19)+11]/7=891/35

=>z=(44/5*3)+5=157/5

hình như sai hay sao, số lớn quá

\(\frac{9x-13}{16}=\frac{7y-11}{19}=\frac{z-5}{3}=k\)

\(\frac{45x-65}{80}=\frac{63y-99}{171}=\frac{27z-45}{27}=k\)

Suy ra

\(k=\frac{45x-65-63y+99+27x-45}{80-171+27}\)

\(k=\frac{9\left(5x-7y+3z\right)-11}{-64}=\frac{81-11}{-64}=-\frac{35}{32}\)

\(\frac{9x-13}{16}=-\frac{35}{32}\Rightarrow x=-16\)

\(\frac{7y-11}{19}=-\frac{35}{32}\Rightarrow y=-\frac{313}{224}\)

\(\frac{z-5}{3}=-\frac{35}{32}\Rightarrow z=\frac{55}{32}\)

thiếu đề bài nhé bạn

\(a,12x=4x-30\Leftrightarrow8x=-30\Leftrightarrow x=-\dfrac{15}{4}\)

\(b,2x-5=x-1\Leftrightarrow2x-x=-1+5\Leftrightarrow x=4\)

\(c,2-5x=5x-10\Leftrightarrow-10x=-12\Leftrightarrow x=\dfrac{6}{5}\)

\(d,9x-6=1x-5\Leftrightarrow8x=1\Leftrightarrow x=\dfrac{1}{8}\)

\(e,2x-5=2x-1\Leftrightarrow2x-2x=-1+5\Leftrightarrow0x=4\) (Vô lí)\(\Rightarrow x\in\varnothing\)

kb  voi mik nha

a: \(P\left(x\right)=x^5+2x^4-9x^3-x\)

\(Q\left(x\right)=5x^4+9x^3+4x^2-14\)

c:: \(M\left(x\right)=P\left(x\right)+Q\left(x\right)=x^5+7x^4+4x^2-x-14\)

d: \(M\left(2\right)=32+7\cdot16+4\cdot4-2-14=144\)

\(M\left(-2\right)=-32+7\cdot16+4\cdot4+2-14=84\)

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