C = 59/10 : 3/2 - ( 5/3 x 9/2 x 14/3) : 7/4

= 59/15 - 35 : 7/4

= 59/15 - 20

= -241/15

\(\frac{1+3+5+...+2009}{1+2+3+...+2010}\)

\(=\frac{\frac{\left[\left(2009-1\right):2+1\right]\left(2009+1\right)}{2}}{\frac{\left(2010+1\right)2010}{2}}\)

\(=\frac{\frac{1005.2010}{2}}{\frac{2011.2010}{2}}\)

\(=\frac{1005.2010}{2}.\frac{2}{2011.2010}\)

\(=\frac{1005}{2011}\)

\(\frac{6:\frac{3}{5}-1\frac{1}{6}.\frac{6}{7}}{4\frac{1}{5}.\frac{10}{11}+5\frac{2}{11}}=\frac{10-\frac{7}{6}.\frac{6}{7}}{\frac{21}{5}.\frac{10}{11}+\frac{57}{11}}=\frac{10-1}{\frac{42}{11}+\frac{57}{11}}=\frac{9}{9}=1\)

A = (29 x 2019 + 71 x 2019) : 100 - 19 

A = [2019 x (29 + 71)] : 100 - 19 

A = (2019 x 100) : 100 - 19 

A = 2019 - 19 

A = 2000 

B = (3/4 + 5/6) : 1\(\frac{7}{12}\)- 1/2 

B = (9/12 + 10/12) : 19/12 - 1/2 

B = 19/12 : 19/12 - 1/2 

B = 1 - 1/2 

B = 1/2

A = (29 x 2019 + 71 x 2019) : 100 - 19 

A = [2019 x (29 + 71)] : 100 - 19 

A = (2019 x 100) : 100 - 19 

A = 2019 - 19 

A = 2000 

a) \(A=4,25.\left(58,47+41,53\right)-125=4,25.100-125=425-125=300\)

b) \(4,25.\left(a+41,53\right)-125=53,5\)

\(\Leftrightarrow4,25.\left(a+41,53\right)=178,5\)

\(\Leftrightarrow a+41,53=42\Rightarrow a=0,47\)

ko hiểu hỏi mik nka , t-i-c-k mik nka

Cho biểu thức : A=4,25*(a+41,53)-125a.Tính giá trị của biểu thức A,khi a = 58,47b.Tìm giá trị của a để A =53,5

3/5-6/8.5/3

3/5-30/24

72/100-150/100

-28/100

\(\frac{3}{5}-\frac{6}{8}:\frac{3}{5}\)

=>\(\left(1-\frac{6}{8}\right):\frac{3}{5}\)

=>\(\frac{1}{4}:\frac{3}{5}\)

=>\(\frac{1}{4}\times\frac{5}{3}\)

=>\(\frac{5}{12}\)

a , Thiếu đề bài:

b, Với A bằng 5 thì : (x+1/2):1/4 = 5

x+1/2 = 5x1/4

x + 1/2 = 5/4

x=5/4 - 1/2

x=3/4

A = 1,6 ; B = 1

Bạn nhớ cho mình nhé!