Giải các hệ

\(\left\{{}\begin{matrix}\sqrt{x+y}+\sqrt{2x+y+2}=7\\3x+2y=23\end{matrix}\right.\)

\(\left\{{}\begin{matrix}x^2+y+x^3y+xy^2+xy=\frac{-5}{4}\\x^4+y^2+xy\left(1+2x\right)=\frac{-5}{4}\end{matrix}\right.\)

\(\left\{{}\begin{matrix}\left(x^2+1\right)+y\left(x+y\right)=7y\\\left(x^2+1\right)\left(x+y-2\right)=-y\end{matrix}\right.\)

\(\left\{{}\begin{matrix}x\left(x+y+1\right)=3\\\left(x+y\right)^2-\frac{5}{x^2}=-1\end{matrix}\right.\)

giải hệ phương trình

a) \(\left\{{}\begin{matrix}\sqrt{2x^2+2y^2}+\sqrt{\frac{4}{3}\left(x^2+xy+y^2\right)}=2\left(x+y\right)\\\sqrt{3x+1}+\sqrt{5x+4}=3xy-y+3\end{matrix}\right.\)

b) \(\left\{{}\begin{matrix}\sqrt{5x^2+2xy+2y^2}+\sqrt{2x^2+2xy+5y^2}=3\left(x+y\right)\\\sqrt{x+2y+1}+2\sqrt[3]{12x+7y+8}=2xy+x+5\end{matrix}\right.\)

c)\(\left\{{}\begin{matrix}x^2+xy+x+3=0\\\left(x+1\right)^2+3\left(y+1\right)+2\left(xy-\sqrt{x^2y+2y}\right)=0\end{matrix}\right.\)

Giải các hệ phương trình sau

\(1)\left\{{}\begin{matrix}\sqrt{x+1}=\sqrt{2}\left(8y^2+8y+1\right)\\4\left(x^3-8y^3\right)-6\left(x^2+4y^2\right)+3\left(x+2y\right)-1=0\end{matrix}\right.\)

\(2)\left\{{}\begin{matrix}3\sqrt{17x^2-y^2-6x+4}+x=6\sqrt{2x^2+x+y}-3y+2\\\sqrt{3x^2+xy+1}=\sqrt{x+1}\end{matrix}\right.\)

\(3)\left\{{}\begin{matrix}x^3+\left(2-y\right)x^2+\left(2-3y\right)x=5\left(x+1\right)\\3\sqrt{y+1}=3x^2-14x+14\end{matrix}\right.\)

\(4)\left\{{}\begin{matrix}4x^2=\left(\sqrt{x^2+1}+1\right)\left(x^2-y^3+3y-2\right)\\x^2+\left(y+1\right)^2=2\left(1+\dfrac{1-x^2}{y}\right)\end{matrix}\right.\)

\(5)\left\{{}\begin{matrix}7x^3+y^3+3xy\left(x-y\right)-12x^2+6x-1=0\\y^2+7y-17=9x+2\left(x+6\right)\sqrt{5-2y}\end{matrix}\right.\)

\(6)\left\{{}\begin{matrix}2x^2+3=4\left(x^2-2yx^2\right)\sqrt{3-2y}+\dfrac{4x^2+1}{x}\\\left(2x+1\right)\sqrt{2-\sqrt{3-2y}}=\sqrt[3]{2x^2+x^3}+x+2\end{matrix}\right.\)

giải hệ phương trình

1, \(\left\{{}\begin{matrix}2x^2+3y=17\\3x^2-2y=6\end{matrix}\right.\)

2, \(\left\{{}\begin{matrix}\left|x-1\right|+\left|y-1\right|=2\\4\left|x-1\right|+3\left|y-1\right|=7\end{matrix}\right.\)

3, \(\left\{{}\begin{matrix}3\sqrt{x-1}+2\sqrt{y}=2\\2\sqrt{x-1}-\sqrt{y}=4\end{matrix}\right.\)

4 , \(\left\{{}\begin{matrix}x+y=2\\\left|2x-3y\right|=1\end{matrix}\right.\)

5 , \(\left\{{}\begin{matrix}2x-y=1\\\left|x-y\right|=\left|2y-1\right|\end{matrix}\right.\)

6,\(\left\{{}\begin{matrix}\left(x-3\right)\left(y+6\right)=xy\\\left(x+2\right)\left(y-2\right)=xy\end{matrix}\right.\)

7 , \(\left\{{}\begin{matrix}\left(x-3\right)\left(2y+5\right)=\left(2x+7\right)\left(y-1\right)\\\left(4x+1\right)\left(3y-6\right)=\left(6x-1\right)\left(2y+3\right)\end{matrix}\right.\)

8 , \(\left\{{}\begin{matrix}4x^2-5\left(y+1\right)=\left(2x-3\right)^2\\3\left(7x+2\right)=5\left(2y-1\right)-3x\end{matrix}\right.\)

1,\(\left\{{}\begin{matrix}x^2+xy-3x+y=0\\x^4+3x^2y-5x^2+y^2=0\end{matrix}\right.\)

2, \(\left\{{}\begin{matrix}\left(2x-1\right)^2+4\left(y-1\right)^2=22\\xy\left(x-1\right)\left(y-2\right)=1\end{matrix}\right.\)

3, \(\left\{{}\begin{matrix}\left(x^2+y^2\right)\left(x+y+1\right)=25\left(y+1\right)\\x^2+xy+2y^2+x-8y=9\end{matrix}\right.\)

4,\(\left\{{}\begin{matrix}5x^2y-4xy^2+3y^2-2\left(x+y\right)=0\\xy\left(x^2+y^2\right)+2=\left(x+y\right)^2\end{matrix}\right.\)