a)\(-1,6:\left(1+\dfrac{2}{3}\right)=-1,6:\dfrac{5}{3}=-\dfrac{8}{5}.\dfrac{3}{5}=\dfrac{-24}{25}\)

b)\(\left(\dfrac{-2}{3}\right)+\dfrac{3}{4}-\left(-\dfrac{1}{6}\right)+\left(\dfrac{-2}{5}\right)=-\dfrac{2}{3}+\dfrac{3}{4}+\dfrac{1}{6}-\dfrac{2}{5}=\dfrac{-40+45+10-24}{60}=\dfrac{-9}{60}=\dfrac{-3}{20}\)

c)\(\left(\dfrac{-3}{7}:\dfrac{2}{11}+\dfrac{-4}{7}:\dfrac{2}{11}\right).\dfrac{7}{33}=\left(\dfrac{-3}{7}.\dfrac{11}{2}+\dfrac{-4}{7}.\dfrac{11}{2}\right).\dfrac{7}{33}=\left[\dfrac{11}{2}\left(\dfrac{-3}{7}+\dfrac{-4}{7}\right)\right].\dfrac{7}{33}=\dfrac{-11}{2}.\dfrac{7}{33}=\dfrac{-7}{6}\)

d)\(\dfrac{-5}{8}+\dfrac{4}{9}:\left(\dfrac{-2}{3}\right)-\dfrac{7}{20}.\left(\dfrac{-5}{14}\right)=\dfrac{-5}{8}-\dfrac{4}{9}.\dfrac{3}{2}+\dfrac{1}{8}=\dfrac{-5}{8}+\dfrac{1}{8}-\dfrac{2}{3}=-\dfrac{7}{6}\)

|x+3|+|y-1|=0

\(\Rightarrow\hept{\begin{cases}\left|x+3\right|\ge0\\\left|y-1\right|\ge0\end{cases}\Rightarrow}\hept{\begin{cases}x+3=0\\y-1=0\end{cases}\Rightarrow}\hept{\begin{cases}x=-3\\y=1\end{cases}}\)

Vậy x=-3 ; y=1

==>| x+3 |= | y—1 |=0

==> x+3= y—1=0

Do đó: x=0–3=y= 0+1=0

Nên: x= (-3); y= 1

1C

2B

3B

4D

5D

6A

7A

8C

9A

10D

11A

a: =>x-4=0 hoặc x+5=0

=>x=4 hoặc x=-5

b: =>39/7:x=13

hay x=3/7

c: \(\Leftrightarrow\left(4.5-2x\right)=\dfrac{11}{4}:\dfrac{4}{9}=\dfrac{99}{16}\)

\(\Leftrightarrow2x=-\dfrac{27}{16}\)

hay x=-27/32

d: \(\Leftrightarrow x\cdot\dfrac{19}{15}=684\)

hay x=540

a. \(\left[{}\begin{matrix}x-4=0\\x+5=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-5\end{matrix}\right.\)

b.\(\Leftrightarrow\dfrac{39}{7}:x=13\)

\(\Leftrightarrow x=13.\dfrac{39}{7}\)

\(\Leftrightarrow x=\dfrac{507}{7}\)

c.\(\Leftrightarrow4,5-2x=\dfrac{99}{16}\)

\(\Leftrightarrow-2x=\dfrac{27}{16}\)

\(\Leftrightarrow x=-\dfrac{27}{32}\)

1) Ta có: \(1+\left(-2\right)+3+\left(-4\right)+...+19+\left(-20\right)\)

\(=\left(-1\right)+\left(-1\right)+\left(-1\right)+...+\left(-1\right)\)

\(=-1\cdot10=-10\)

2) Ta có: \(1-2+3-4+...+99-100\)

\(=\left(-1\right)+\left(-1\right)+...+\left(-1\right)\)

\(=-1\cdot50=-50\)

mình cảm ơn ạ .

\(\dfrac{3}{1.4}+\dfrac{3}{4.7}+...+\dfrac{3}{100.103}\\ =1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{100}-\dfrac{1}{103}\\ =1-\dfrac{1}{103}\\ =\dfrac{102}{103}\)

e: =113+87-64-26

=200-90=110

f: =244+66-152-48

=310-200

=110

g: =437-437+123-33

=123-33

=90

h: =599-499+387

=387+100

=487

i: =4*25*8*125

=100*1000

=100000

k: =2*5*3*19

=57*10

=570

l: =78(7+3)

=78*10=780

m: =64(49-39)

=64*10=640

n: =19(41+59)

=19*100

=1900

e: =113+87-64-26

=200-90=110
sao 64-26 lại bằng 90 ạ?
có nhầm khum ạ

Đổi: 300m2 = 3000000cm2

Diện tích 1 viên gạch là:

50 x 50 = 2500 (cm2)

Vậy số viên gạch có là:

3000000 : 2500 = 1200 (viên)

Đ/S: 1200 viên

D

D