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125: (2\(x\) - 3\(x\)) = 55: 53
125: (-\(x\)) = 25
\(x\) = - 125 : 25
\(x\) = - 5
3/1.4+3/4.7+....+3/97.100
= 1-1/4+1/4-1/7+....+1/97-1/100
=1-1/100
=99/100
(26 + 53 ) +(42 -26-55-53)
=79 + ( 16 -55 - 53 )
=79 + (-39-53)
=79 -39 - 53
=40 - 53 = -13
a) 25 - 3x = 13
3x = 25 - 13
3x = 12
x = 12 : 3
x = 4
b) 13 + 3(130 - 3x) = 313
3(130 - 3x) = 313 - 13
3(130 - 3x) = 300
130 - 3x = 300 : 3
130 - 3x = 100
3x = 130 - 100
3x = 30
x = 30 : 3
x = 10
a, ( - 125 ) + 100 + 80 + 125 + 20
= ( - 125 + 125 ) + 100 + ( 80 + 20 )
= 0 + 100 + 100
= 200
b, 27 + 55 + ( - 17 ) + ( - 55 )
= ( 27 - 17 ) + ( 55 - 55 )
= 10 + 0
= 10
c, ( - 92 ) + ( - 251 ) + ( - 8 ) + 251
= ( - 92 - 8 ) + ( - 251 + 251 )
= - 100 + 0
= - 100
d, ( - 31 ) + ( - 95 ) + 131 + ( - 5 )
= ( - 31 + 131 ) + ( - 95 - 5 )
= 100 + ( - 100 )
= 0
a) (-125) + 100 + 80 + 125 + 20
= [(-125) + 125] + 100 + (80 + 20)
= 0 + 100 + 100
= 200
b) 27 + 55 + (-17) + (-55)
= [27 + (-17)] + [55 + (-55)]
= 10 + 0
= 10
c) (-92) + (-251) + (-8) + 251
= [(-92) + (-8)] + [(-251) + 251]
= (-100) + 0
= -100
d) (-31) + (-95) + 131 + (-5)
= [(-31) + 131] + [(-95) + (-5)]
= 100 + (-100)
= 0
\(a,-81.46-81.55+81\)
\(=81.\left(-46\right)-81.55+81\)
\(=81.\left(-46-55+1\right)\)
\(=81.\left(-100\right)\)
\(=-8100\)
\(b,35.\left(17-5\right)-17.\left(35-5\right)\)
\(=35.17-35.5-17.35+17.5\)
\(=\left(35.17-17.35\right)-\left(35.5-17.5\right)\)
\(=35.\left(17-17\right)-5.\left(35-17\right)\)
\(=35.0-5.18\)
\(=0-90\)
\(=-90\)
Cách 2 : \(35.\left(17-5\right)-17.\left(35-5\right)\)
\(=35.12-17.30\)
\(=420-510\)
\(=-90\)
\(c,-125.6.\left(-8\right).\left(-50\right)\)
\(=\left(-125\right).\left(-8\right).6.\left(-50\right)\)
\(=1000.\left(-300\right)\)
\(=-300000\)
=> 125-5.(3x-1)=52
=> 125-5.(3x-1)=25
=> 5.(3x-1)=125-25
=> 5.(3x-1)=100
=> 3x-1=100:5
=> 3x-1=20
=> 3x=20+1
=> 3x=21
=> x=21:3
Vậy x=7.