5/15+14/25-12/9+2/7+11/25=(5/15+2/7)+(14/25+11/25)-12/9=17/35+1-12/9=16/105

=\(\left(\frac{5}{15}-\frac{12}{9}\right)+\left(\frac{14}{25}+\frac{11}{15}\right)+\frac{2}{7}\)

=\(\left(\frac{1}{3}-\frac{4}{3}\right)+1+\frac{2}{7}\)

=\(\frac{-3}{3}+1+\frac{2}{7}=-1+1+\frac{2}{7}\)

=\(\frac{2}{7}\)

\(\frac{8^4.3^5-4^6.9^3}{4^6.9^3+4^8.3^5}=\frac{8^4}{4^8}=\frac{4096}{65536}=\frac{1}{16}\)

k nha 

\(\frac{8^4.3^5-4^6.9^3}{4^6.9^3+4^8.3^5}=\frac{2^{12}.3^5-2^{12}.3^6}{2^{12}.3^6+2^{16}.3^5}=\frac{2^{12}.3^5\left(1-3\right)}{2^{12}.3^5\left(3-2\right)}=\frac{-2}{1}\) = -2

Xin một câu quote nha! ^^

c) (0.01):2,5=(0,75x).(0,75)

         0,004 =(0,75x).(0,75)

         => x=0.0071

Đề này bn xem lại coi có đúng k

A) \(\frac{10}{12}\)+\(2\)- /\(\frac{-2}{3}\)/ -\(\frac{3}{4}\)= \(\frac{10}{12}\)+2-\(\frac{2}{3}\)-\(\frac{3}{4}\)= \(\frac{10}{12}\)+\(\frac{24}{12}\)-\(\frac{8}{12}\)-\(\frac{9}{12}\)=\(\frac{17}{12}\)

tương tự bài B= \(\frac{59}{40}\)

mk hk bk ghi dáu GTTĐ nên mk ghi như thế 

bạn tính kết quả trong dấu GT tuyệt đối rồi bạn mở dấu GTTĐ bằng cách cho số đó trở thành số dương là được

chúc bn may mắn

\(\left(-1\frac{1}{2}\right)\left(-1\frac{1}{3}\right)\left(-1\frac{1}{4}\right)...\left(-1\frac{1}{2003}\right)\left(-1\frac{1}{2004}\right)\)

\(=-\frac{3}{2}.\frac{4}{3}.\frac{5}{4}.....\frac{2004}{2003}.\frac{2005}{2004}\)

\(=-\frac{3.4.5.....2004.2005}{2.3.4.....2003.2004}=\frac{-2005}{2}\)

\(A=9-\frac{3}{5}+\frac{2}{3}-7-\frac{7}{5}+\frac{3}{2}-3+\frac{9}{5}-\frac{5}{2}\)

\(=\left(9-7-3\right)+\left(\frac{9}{5}-\frac{7}{5}-\frac{3}{5}\right)+\left(\frac{3}{2}-\frac{5}{2}\right)\)

\(=-2-\frac{1}{5}=-\frac{11}{5}\)

A = 27/12

Hok tốt

a. (0,125)³ . 512

= \(\frac{1}{512}\).512

= 1

b. \(\left(\frac{90}{15}\right)^3\)

= 6³ = 216

c. [(0,1)³]

= \(\frac{1}{1000}\)

d. \(\left[\left(\frac{-1}{27}\right)^3\right]^6\)

= \(\left(-\frac{1}{27}\right)^{18}\)

a, \(\frac{\left(\frac{1}{9}\right)^6\cdot\left(\frac{3}{8}\right)^7}{\left(\frac{1}{3}\right)^{13}\cdot\left(\frac{1}{2}\right)^{22}.3^6}\)

\(=\frac{\left(\frac{1}{\left(3^2\right)^6}\right)\cdot\left(\frac{1}{2}\cdot\frac{1}{2}\cdot\frac{1}{2}\cdot3\right)^7}{\left(\frac{1}{3}\right)^{13}.\left(\frac{1}{2}\right)^{22}.3^6}=\frac{\frac{1}{3^{12}}\cdot\left(\frac{1}{2}\right)^{21}\cdot3^7}{\frac{1}{3^{13}}\cdot\left(\frac{1}{2}\right)^{22}.3^6}\)

                                                              \(=\frac{3}{\frac{1}{3}\cdot\frac{1}{2}}=3\div\frac{1}{6}=3.6=18\)

b, Làm tương tự nha bn 

a) \(\frac{\left(0,8\right)^2}{\left(0,4\right)^2}=4\)

b) 75⁴ : 25⁴ + 2012⁰

= (75:25)⁴  + 1

= 3⁴ + 1 = 81 + 1 = 82

a) \(\frac{\left(0,8\right)^2}{\left(0,4\right)^2}=\left(\frac{0,8}{0,4}\right)^2=2^2=4\)

b)  \(75^4:25^4+2012^0\)

\(=\left(75:25\right)^4+2012^0\)

\(=3^4+2012^0\)

\(=81+1\)

\(=82\)