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30 tháng 9 2017

\(\left(5+\frac{2\sqrt{6}}{\sqrt{3}}+\sqrt{2}\right)-\left(5-\frac{2\sqrt{6}}{\sqrt{3}}-\sqrt{2}\right)\)

=\(5+\frac{2\sqrt{6}}{\sqrt{3}}+\sqrt{2}-5+\frac{2\sqrt{6}}{\sqrt{3}}+\sqrt{2}\)

=\(\left(5-5\right)+\left(\frac{2\sqrt{6}}{\sqrt{3}}+\frac{2\sqrt{6}}{\sqrt{3}}\right)+\left(\sqrt{2}+\sqrt{2}\right)\)

=\(0+\frac{4\sqrt{6}}{\sqrt{3}}+2\sqrt{2}\)

=\(\frac{4\sqrt{2}.\sqrt{3}}{\sqrt{3}}+2\sqrt{2}\)

=\(4\sqrt{2}+2\sqrt{2}\)

=\(6\sqrt{2}\)

24 tháng 11 2021

\(a,=\dfrac{\sqrt{5}+1+\sqrt{5}-1}{\left(\sqrt{5}-1\right)\left(\sqrt{5}+1\right)}=\dfrac{2\sqrt{5}}{4}=\dfrac{\sqrt{5}}{2}\\ b,=\sqrt{\left(3-\sqrt{5}\right)^2}+\left|2-\sqrt{5}\right|=3-\sqrt{5}+\sqrt{5}-2=1\\ c,=\dfrac{2\left(\sqrt{5}-\sqrt{3}\right)}{2}-\dfrac{-\sqrt{3}\left(\sqrt{5}-\sqrt{3}\right)}{\sqrt{5}-\sqrt{3}}=\sqrt{5}-\sqrt{3}+\sqrt{3}=\sqrt{5}\)

9 tháng 11 2021

\(a,=\dfrac{\sqrt{2}\left(\sqrt{2}+1\right)}{\sqrt{2}+1}=\sqrt{2}\\ b,=\dfrac{\sqrt{5}\left(\sqrt{3}-1\right)}{1-\sqrt{3}}=-\sqrt{5}\\ c,=\dfrac{\sqrt{6}\left(\sqrt{2}-1\right)}{2\left(\sqrt{2}-1\right)}=\dfrac{\sqrt{6}}{2}\)

1:

\(A=\sqrt{x^2+\dfrac{2x^2}{3}}=\sqrt{\dfrac{5x^2}{3}}=\left|\sqrt{\dfrac{5}{3}}x\right|=-x\sqrt{\dfrac{5}{3}}\)

2: \(=\left(\dfrac{\sqrt{100}+\sqrt{40}}{\sqrt{5}+\sqrt{2}}+\sqrt{6}\right)\cdot\dfrac{2\sqrt{5}-\sqrt{6}}{2}\)

\(=\dfrac{\left(2\sqrt{5}+\sqrt{6}\right)\left(2\sqrt{5}-\sqrt{6}\right)}{2}\)

\(=\dfrac{20-6}{2}=7\)

a: \(=\dfrac{\sqrt{3}\left(\sqrt{5}-2\right)}{\sqrt{5}-2}-3\sqrt{3}+\dfrac{\sqrt{3}\left(\sqrt{3}+\sqrt{2}\right)}{\sqrt{3}+\sqrt{2}}\)

\(=\sqrt{3}-3\sqrt{3}+\sqrt{3}=-\sqrt{3}\)

b: \(=\left(\left(2-2\sqrt{5}\right)\left(\sqrt{5}+2\right)+\sqrt{3}\right)\left(\sqrt{5}-\sqrt{3}\right)\)

\(=\left(2\sqrt{5}+4-10-4\sqrt{5}+\sqrt{3}\right)\left(\sqrt{5}-\sqrt{3}\right)\)

\(=\left(-2\sqrt{5}+\sqrt{3}-6\right)\left(\sqrt{5}-\sqrt{3}\right)\)

\(=-20+2\sqrt{15}+\sqrt{15}-3-6\sqrt{5}+6\sqrt{3}\)

\(=-23+3\sqrt{15}-6\sqrt{5}+6\sqrt{3}\)

17 tháng 1 2022

tự làm

19 tháng 7 2023

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4 tháng 12 2020

Làm luôn nhé

\(2B=21.2\left[\left(\sqrt{2+\sqrt{3}}+\sqrt{3-\sqrt{5}}\right)-6\left(\sqrt{2-\sqrt{3}}+\sqrt{3+\sqrt{5}}\right)\right]^2-2.15\sqrt{15}\)

\(2B=21\left(\sqrt{3}+1+\sqrt{5}-1\right)^2-6\left(\sqrt{3}-1+\sqrt{5}-1\right)^2-30\sqrt{15}\)

\(2B=21\left(\sqrt{3}+\sqrt{5}\right)^2-6\left(\sqrt{3}+\sqrt{5}\right)^2-30\sqrt{15}\)

\(2B=15\left(\sqrt{3}+\sqrt{5}\right)^2-30\sqrt{15}\)

\(2B=15\left(8+2\sqrt{15}\right)-30\sqrt{15}\)

\(2B=120+30\sqrt{15}-30\sqrt{5}\)

\(2B=120\)

\(B=60\)

14 tháng 1 2022

a)

 \(2\sqrt{5}\)+ I1-\(\sqrt{5}\)I

\(2\sqrt{5}\)+1-\(\sqrt{5}\)

1+\(\sqrt{5}\)

b: \(=\dfrac{\sqrt{3}-1+\sqrt{3}+1-4\sqrt{3}}{2}=-\sqrt{3}\)