3/x-2=2x-1/x-2  - x 

<=> 3/x-2=2x-1/x-2  -  x^2-2x/x-2

<=> 3= 2x-1-x^2+2x

<=>x^2-4x+4=0

=> (x-2)^2=0

=> x=2

\(\left(5x-1\right)\left(x+2\right)-3\left(x+2\right)^2-2\left(x-3\right)\left(x+2\right)\)

\(=\left(x+2\right)\left(5x-1-2x+6\right)-3\left(x^2+4x+4\right)\)

\(=\left(x+2\right)\left(3x+5\right)-3x^2-12x-12=-x-2\)

x(x-1)=1-x²

x²-x=1-x²

2x²-x-1=0

\(\hept{\begin{cases}x=1\\x=\frac{-1}{2}\end{cases}}\)

x(x-1)= (1-x)(1+x)

x(x-1)+(x-1)(x+1)=0

(x-1) (x + x+1)= 0

(x-1)(2x+1)=0

x=1 hoặc x = -1/2

Câu 1: D

Câu 2: B

Câu 3: D

Câu 4: C

Câu 5: A

toán lớp 8 ah răng lại hỏi chắc là câu ni anh mi ko biết hầy

A = ( x - 2 )² + 5

   =  ( x - 2 ) ² + 5 > hoặc = 5

=> GTNN là 5

B = x²+ 2x + 3

   = x² + 2 .x . 1 + 1 + 2

   = ( x + 1 )² + 2 >hoặc = 2

=> GTNN là 2

\(A=\left(x-2\right)^2+5\)

vì \(\left(x-2\right)^2\ge0\Rightarrow\left(x-2\right)^2+5\ge5\)

vậy min A=5 khi x=2

\(B=x^2+2x+3\)

\(=x^2+2x+1+2\)

\(=\left(x+1\right)^2+2\ge2\)

vậy Min B=2 khi x=-1

\(2x^2+6x-8=0\)

<=> \(2x^2-2x+8x-8=0\)

<=> \(2x\left(x-1\right)+8\left(x-1\right)=0\)

<=> \(\left(2x+8\right)\left(x-1\right)=0\)

<=> \(\hept{\begin{cases}2x+8=0\\x-1=0\end{cases}}\)

<=> \(\hept{\begin{cases}x=-4\\x=1\end{cases}}\)

\(2x^2-x-1=0\)

<=> \(2x^2-2x+x-1=0\)

<=> \(2x\left(x-1\right)+\left(x-1\right)=0\)

<=> \(\left(2x+1\right)\left(x-1\right)=0\)

<=> \(\hept{\begin{cases}2x+1=0\\x-1=0\end{cases}}\)

<=> \(\hept{\begin{cases}x=-\frac{1}{2}\\x=1\end{cases}}\)

\(4x^2-5x-9=0\)

<=> \(4x^2+4x-9x-9=0\)

<=> \(4x\left(x+1\right)-9\left(x+1\right)=0\)

<=> \(\left(4x-9\right)\left(x+1\right)=0\)

<=> \(\hept{\begin{cases}4x-9=0\\x+1=0\end{cases}}\)

<=> \(\hept{\begin{cases}x=\frac{3}{2}\\x=-1\end{cases}}\)

học tốt

\(2x^2+6x-8=0\)

\(< =>2x^2-2x+8x-8=0\)

\(\Leftrightarrow2x\left(x-1\right)+8\left(x-1\right)=0\)

\(\Leftrightarrow\left(2x+8\right)\left(x-1\right)=0\)

\(\Leftrightarrow\left(2x+8\right)\left(x-1\right)=0\)

\(\Leftrightarrow2x+8=0\)hoặc \(x-1=0\)

\(\Leftrightarrow x=-4\)hoặc \(x=1\)