1/6=1*8/ 6*8=8/48

2/8=2*6/ 8*6=12/48

\(\frac{1}{6}=\frac{4}{24}\)

\(\frac{2}{8}=\frac{6}{24}\)

vậy ..

học tốt

\(\frac{1}{6}=\frac{4}{24}\)

\(\frac{2}{8}=\frac{6}{24}\)

Cần điểm hỏi đáp

Cách 1: Ta sẽ lấy phân số trung gian cho bài toán sẽ là \(\dfrac{15}{5}\)

Ta có:

\(\dfrac{16}{5}>\dfrac{15}{5}\)

Mà \(\dfrac{15}{5}=3\) nên \(\dfrac{16}{5}>3\)

Vậy \(\dfrac{16}{5}>3\)

Cách 2:

Ta có:

\(\dfrac{16}{5}=\dfrac{15}{5}+\dfrac{1}{5}\)

Mà \(\dfrac{15}{5}=3\) nên \(\dfrac{15}{5}+\dfrac{1}{5}>3\)

Vậy \(\dfrac{16}{5}>3\)

\(\dfrac{25}{47}< \dfrac{56}{53}\) vì \(\dfrac{25}{47}< 1< \dfrac{56}{53}\)

\(\dfrac{1313}{2121}=\dfrac{13}{21}\) vì \(\dfrac{1313}{2121}=\dfrac{13\times101}{21\times101}=\dfrac{13}{21}\)

\(2b,\)\(54\times47-47\times53-20-27.\)

\(=47\times54-47\times53-47\)

\(=47\times\left(54-53-1\right)\)

\(=47\times0=0\)

\(2c,\)\(10000-47\times72-47\times28\)

\(=100\times100-47\times\left(72+28\right)\)

\(=100\times100-47\times100\)

\(=100\times\left(100-47\right)\)

\(=100\times53=5300\)

2b

54 x 47 - 47 x 53 - 20 - 27 = 47 x ( 54 - 53 ) - 20 - 27 = 47 - 20 - 27 = 47 - ( 20 + 27 ) = 47 - 47 = 0

2c

10000 - 47 x 72 - 47 x 28 = 10000 - 47 x ( 72 - 28 ) = 10000 - 47 x 44 = 10000 - 2068 = 7932

(145 x 99 + 145 ) - ( 143 x 102 – 143 × 2 ) + 54 x 47 - 47 x 53 - 20 - 27

= 145 × (99 + 1) – 143 × (102 – 2) + 47 × (54 – 53) – (20 + 27)

= 145 × 100 – 143 × 100 + 47 × 1 – 47

= 100 × (145 – 143) + (47 – 47)

= 100 × 2 + 0

= 200

(145 x 99 + 145 ) - ( 143 x 102 – 143 × 2 ) + 54 x 47 - 47 x 53 - 20 - 27

= 145 × (99 + 1) – 143 × (102 – 2) + 47 × (54 – 53) – (20 + 27)

= 145 × 100 – 143 × 100 + 47 × 1 – 47

= 100 × (145 – 143) + (47 – 47)

= 100 × 2 + 0

= 200

giỏi

\(\dfrac{7}{12}=\dfrac{3}{12}+\dfrac{4}{12}=\dfrac{1}{4}+\dfrac{1}{3}\)

\(\dfrac{13}{27}=\dfrac{9}{27}+\dfrac{4}{27}=\dfrac{1}{3}+\dfrac{4}{27}\)

\(\dfrac{7}{12}\) = \(\dfrac{1+6}{12}\) = \(\dfrac{1}{12}\) + \(\dfrac{6}{12}\) = \(\dfrac{1}{12}\) + \(\dfrac{1}{2}\)

\(\dfrac{7}{12}\) = \(\dfrac{3+4}{12}\) = \(\dfrac{3}{12}\) + \(\dfrac{4}{12}\) = \(\dfrac{1}{4}\) + \(\dfrac{1}{3}\)

\(\dfrac{13}{27}\) = \(\dfrac{1+12}{27}\) = \(\dfrac{1}{27}\) + \(\dfrac{12}{27}\) = \(\dfrac{1}{27}\) + \(\dfrac{4}{9}\)

\(\dfrac{13}{27}\) = \(\dfrac{4+9}{27}\) = \(\dfrac{4}{27}\) + \(\dfrac{9}{27}\) = \(\dfrac{4}{27}\) + \(\dfrac{1}{3}\)

\(\dfrac{13}{27}\) = \(\dfrac{6+7}{27}\) = \(\dfrac{6}{27}\) + \(\dfrac{7}{27}\) = \(\dfrac{2}{9}\) +  \(\dfrac{7}{27}\)