Cho mik xin lại đề bài mik nhìn ki hiểu j hết

1)2763 + 152 = 2915

2)(-7) + (-14) = -21

3)(-35) + (-9) = -44

câu nầy hơn khó nên mình ko giải đc bạn đợ mình giải đã

1) 2763 + 152 = 2951

2)(-7) + (-14) = -21

1) 2763 +152 =2915

2) (-7) +(-14) = -21

3) (-35) + (-9) = -44

4) (-5) + (-248) = -253

5) (-23) + 105 = 82

6) 78 + (-123) = -45

7) 23 +(-13) = 10

8) (-23) +13 = -10

9) 26 + (-6) = 20

10) (-75) +50 = -25

11) 80 + (-220) = -140

12) (-23) + (-13) = -36

13) (-26) + (-6) = -32

14) (-75) + (-50) = -125

15) ❏-18❏ + (-12) = -17❏ -12

16)17 + ❏ - 33❏ = 17 -32❏

17) (-20) +❏ - 88❏ = -20 -87❏

18) ❏- 3❏+ ❏5❏ = ❏5❏ -2❏

19)❏-37❏+❏15❏ = ❏15❏ -36❏

20) ❏-37❏+(-❏15❏) = -❏15❏ - 36❏

21) (-❏-32❏) +❏5❏ = ❏5❏ -33❏

22) (-❏-22❏) + (-❏16❏) = -❏16❏ -23❏

23) (-23) +13 +(-17) +57 = 30

24) 14 +6 + (-9) + (-14) = -3

25) (-123 ) +❏-13❏+(-7) = -130-12❏

26) ❏0❏ + ❏45❏ +(-❏-455)❏+❏-796❏ = ❏45❏-❏\(^2\) -1250❏

a; \(\dfrac{9}{27}\) + \(\dfrac{7}{-49}\)

= \(\dfrac{1}{3}\) - \(\dfrac{1}{7}\)

= \(\dfrac{7}{21}\) - \(\dfrac{3}{21}\)

= \(\dfrac{4}{21}\)

b; - \(\dfrac{12}{10}\) + \(\dfrac{-25}{30}\)

   =  - \(\dfrac{6}{5}\) - \(\dfrac{5}{6}\)

   = -\(\dfrac{36}{30}\) - \(\dfrac{25}{30}\)

  = \(\dfrac{-61}{30}\) 

c; \(\dfrac{-20}{35}\) + \(\dfrac{-16}{-24}\)

 =  - \(\dfrac{4}{7}\) + \(\dfrac{2}{3}\)

= - \(\dfrac{12}{21}\) + \(\dfrac{14}{21}\)

=  \(\dfrac{2}{21}\)

d; - \(\dfrac{21}{77}\) + \(\dfrac{10}{-35}\)

 = - \(\dfrac{3}{11}\) - \(\dfrac{2}{7}\)

 = - \(\dfrac{21}{77}\) -  \(\dfrac{22}{77}\)

= - \(\dfrac{43}{77}\)

Đặt : \(A=\frac{1}{20.23}+\frac{1}{23.26}+\frac{1}{26.29}+...+\frac{1}{77.80}\)

\(\Rightarrow3A=\frac{3}{20.23}+\frac{3}{23.26}+\frac{3}{26.29}+...+\frac{3}{77.80}\)

\(\Rightarrow3A=\frac{1}{20}-\frac{1}{23}+\frac{1}{23}-\frac{1}{26}+\frac{1}{26}-\frac{1}{29}+...+\frac{1}{77}-\frac{1}{80}\)

\(\Rightarrow3A=\frac{1}{20}+\left(\frac{1}{23}-\frac{1}{23}\right)+\left(\frac{1}{26}-\frac{1}{26}\right)+...+\left(\frac{1}{77}-\frac{1}{77}\right)-\frac{1}{80}\)

\(\Rightarrow3A=\frac{1}{20}-\frac{1}{80}\)

\(\Rightarrow3A=\frac{3}{80}\)

\(\Rightarrow A=\frac{3}{80}:3\)

\(\Rightarrow A=\frac{1}{80}\)

Vì 80 > 79 nên \(\frac{1}{80}< \frac{1}{79}\)hay \(A< \frac{1}{79}\)

~ Hok tốt ~

Ta có :

\(\frac{1}{20.23}+\frac{1}{23.26}+...+\frac{1}{77.80}\)

\(=\frac{1}{3}\left(\frac{3}{20.23}+\frac{3}{23.26}+...+\frac{3}{77.80}\right)\)

\(=\frac{1}{3}\left(\frac{1}{20}-\frac{1}{23}+\frac{1}{23}-\frac{1}{26}+...+\frac{1}{77}-\frac{1}{80}\right)\)

\(=\frac{1}{3}\left(\frac{1}{20}-\frac{1}{80}\right)\)

\(=\frac{1}{3}.\frac{3}{80}\left(\frac{3}{80}< 1\right)\)

\(\Leftrightarrow\frac{1}{20.23}+\frac{1}{23.26}+...+\frac{1}{77.80}< \frac{1}{3}\left(đpcm\right)\)

\(M=\frac{1}{20.23}+\frac{1}{23.26}+\frac{1}{26.29}+...+\frac{1}{77x80}\)

\(M=\frac{1}{20}-\frac{1}{23}+\frac{1}{23}-\frac{1}{26}+\frac{1}{26}-\frac{1}{29}+...+\frac{1}{77}-\frac{1}{80}\)

\(M=\frac{1}{20}-\frac{1}{80}=\frac{3}{80}\)

\(\frac{3}{80}=\frac{3x9}{80x9}=\frac{27}{720};\frac{1}{9}=\frac{1x80}{9x80}=\frac{80}{720}\)

Vì \(\frac{27}{720}< \frac{80}{720}\Rightarrow\frac{3}{80}< \frac{1}{9}\Rightarrow M< \frac{1}{9}\)

          #~Will~be~Pens~#