Ta có:

\(A=\frac{2003\times2004-1}{2003\times2004}=\frac{2003\times2004}{2003\times2004}-\frac{1}{2003\times2004}=1-\frac{1}{2003\times2004}\)

\(B=\frac{2004\times2005-1}{2004\times2005}=\frac{2004\times2005}{2004\times2005}-\frac{1}{2004\times2005}=1-\frac{1}{2004\times2005}\)

Vì \(\frac{1}{2003\times2004}>\frac{1}{2004\times2005}\Rightarrow A< B\)

cảm ơn bạn nhiều

(2004-1)(2004+1)+200/2004.2004+199

=2004^2-1+200/2004^2+199

=2004^2+199/2004^2+199

=1

\(\frac{2003.2005+200}{2004.2004+199}\)

= \(\frac{2003.\left(2004+1\right)+200}{\left(2003+1\right).2004+199}\)

= \(\frac{2003.2004+2003+200}{2003.2004+2004+199}\)

= \(\frac{2003.2004+2203}{2003.2004+2203}\)

= \(1\)

                 ~~~~Hok tốt~~~~

=2006×(2004+1)-1/2004×2006+2005

=2006×2004+2006×1-1/2004×2006+2005

=2006×2004+2005/2004×2006+2005

=1

\(=\frac{2006.2004+2006-1}{2004.2006+2005}=\frac{2006.2004+2005}{2004.2006+2005}=1\)

Việt làm đúng rồi nên mik ko Cần giải cho bạn nữa ,OK?

\(\frac{2006\times2004-9}{1995+2004\times2005}=\frac{\left(2005+1\right)\times2004-9}{1995+2004\times2005}\)

\(=\frac{2005\times2004+2004-9}{2004\times2005+1995}\)

\(=\frac{2005\times2004+1995}{1995+2004\times2005}\)

\(=1\)

2006x 2004 -9/1995 +2004x 2005

=(2005+1)x2004 -9/1995+2004x2005

=2005x2004+2004 x1-9/1995+2005x2004

=2005x2004+2004-9/1995+2004x2005

=2005x2004+1995/1995+2005x2004

=1

\(\frac{2006\times2004-9}{2004\times2005+1995}=\frac{2005\times2004+2004-9}{2004\times2005+1995}=\frac{2005\times2004+1995}{2004\times2005+1995}=1\)

ket qua la 1

\(a,\left(\frac{1}{2}\cdot\frac{1}{3}+\frac{1}{4}-\frac{1}{5}\right):\frac{1}{4}:\frac{1}{6}\)

\(=\left(\frac{1}{6}+\frac{1}{4}-\frac{1}{5}\right)\cdot\frac{1}{4}\cdot\frac{1}{6}\)

\(=\left(\frac{10}{60}+\frac{15}{60}-\frac{12}{60}\right)\cdot\frac{1}{24}\)

\(=\frac{13}{60}\cdot\frac{1}{24}\)

\(=\frac{13}{1440}\)

\(b,\frac{2006\cdot2005-1}{2004\cdot2006+2005}\)

 \(\frac{2006\cdot2005-1}{2004\cdot2006+2005}\)

\(=\frac{2006\cdot\left(2004+1\right)-1}{2004 \cdot2006+2005}\)

\(=\frac{2006\cdot2004+2006\cdot1-1}{2004\cdot2006+2005}\)

\(=\frac{2006\cdot2004+2005}{2004\cdot2006 +2005}=1\)

Mình nghĩ phần b, ko có cách 2 đâu bạn .

Đáp số hình như là 0

Đáp số là 1

Lấy máy tính mà tính.Dell rảnh OK

2006*2004-9=4020015

1995+014*2005(xem lại 0,14 hay 14