(2x-1)(2x+1)(4x² +1)

= (4x² - 1)(4x²+1)

=16x⁴ - 1 

(2x-1).(2x+1).(4x^2+1)

= (4x^2 - 1).(4x^2+1)

=  (4x^2)^2  -  1

=  16x^4  - 1

( A   –   B ) 3   =   ( A   +   ( - B ) ) 3       =   A 3   +   3 . A 2 . ( - B )   +   3 . A . ( - B ) 2   +   ( - B ) 3       =   A 3   –   3 A 2 B   +   3 A B 2   –   B 3     = >   ( A   –   B ) 3   =   A 3   –   3 A 2 B   –   3 A B 2   +   B 3

là sai

Đáp án cần chọn là: B

\(\left(3x^2+\dfrac{2}{3}y\right)^2\)

\(=\left(3x^2\right)^2+2.3x.\dfrac{2}{3}y+\left(\dfrac{2}{3}y\right)^2\)

\(=9x^4+4xy+\dfrac{4}{9}y^2\)

(3x²+\(\dfrac{2}{3}\)y)²

=9\(x^4\)+\(\dfrac{4}{9}\)\(y^2\)

làm gì có cái hàng đẳng thức nào như thế .-.

a) \(12\left(2x-5\right)^2-3\left(1+4x\right)\left(4x-1\right)\)

\(=12\left[\left(2x\right)^2-2.2x.5+5^2\right]-3\left(4x+1\right)\left(4x-1\right)\)

\(=12\left(4x^2-20x+25\right)-3\left[\left(4x\right)^2-1\right]\)

\(=48x^2-240x+300-3\left(16x^2-1\right)\)

\(=48x^2-240x+300-48x^2+3\)

\(=-240x+303\)

\(=x^3+9x^2+27x+27\)

\(x^2-1=x^2-1^2=\left(x-1\right)\left(x+1\right)\)

Con ốc sên nhé bạn 

(5-y²)(5+y²)

= 5² - (y²)²

= 25 - y⁴

Áp dụng HĐT: (A-B)(A+B) = A² - B²

Chọn B

B

(1𝑦/3+3)^3

(𝑦/3+3)^3

(𝑦/3+3⋅3/3)^3

(𝑦+3⋅3/3)^3

(𝑦+9/3)^3

\(\left(\dfrac{1}{3}y+3\right)^3=\dfrac{1}{27}y^3+y^2+9y+27\)