3:

a: (a-b+c)-(c-b-a)

=a-b+c-c+b+a

=2a

b: \(-\left(a-b\right)+\left(b-c+a\right)-\left(a+b-c\right)\)

\(=-a+b+b-c+a-a-b+c\)

\(=b-a\)

c: \(-\left(a-b-c\right)-\left(-a+b+c\right)-\left(a-b+c\right)\)

\(=-a+b+c+a-b-c-a+b-c\)

\(=-a+b-c\)

2:

a: \(12-\left(-12\right)=12+12=24\)

b: \(-\left(35-49\right)+\left(27-49\right)=-35+49+27-49\)

=-35+27

=-8

c: \(47-\left(59-63\right)+\left(63-47\right)\)

\(=47-59+63+63-47\)

=126-59

=67

d: \(-\left(-20\right)-\left(-30\right)-70\)

=20+30-70

=50-70

=-20

\(A< B\) \(nha\)\(bn\)

A<B nha

A

A

a: 58/63=3190/3465

36/55=2268/3465

=>58/63>36/55

b: 27/53=1998/3922

36/74=1908/3922

=>27/53>36/74

a: 58/63=3190/3465

36/55=2268/3465

=>58/63>36/55

b: 27/53=1998/3922

36/74=1908/3922

=>27/53>36/74

C

C nhé

xét A và B có :

\(\frac{42}{47}\)<\(\frac{42}{45}\) (1)

theo tính chất bắc cầu ta có ;

\(\frac{37}{51}\)+\(\frac{14}{51}\)=1        ;         \(\frac{29}{37}\)+\(\frac{8}{37}\)=1  

\(\frac{31}{35}\)+\(\frac{4}{35}\)=1          ;          \(\frac{49}{63}\)+\(\frac{14}{63}\)=1

Mà \(\frac{14}{51}\)>\(\frac{14}{63}\)=> \(\frac{37}{51}\)< \(\frac{49}{63}\)(2)

ta lại có :  \(\frac{4}{35}\)=\(\frac{8}{70}\)( nhân cả tử và mẫu vs 2 )

mà \(\frac{8}{70}\)<\(\frac{8}{37}\)nên \(\frac{4}{35}\)<\(\frac{8}{37}\)=>\(\frac{29}{37}< \frac{31}{35}\)(3)

Từ (1) ; (2);(3)=>\(\frac{42}{47}+\frac{37}{51}+\frac{29}{37}< \frac{42}{45}+\frac{49}{63}+\frac{31}{35}\)

35 x 36 + 36 x 63 + 36 : 1/2​

= 35 x 36 + 36 x 63 + 36 x 2

= 36 x ( 35 + 63 + 2 )

= 36 x 100

= 3 600

/HT\

=35x36+36x63+36x2 (nếu bn ko hiểu tại sao mik nhân 2 thì: 36 : 1/2 = 36 x 2/1= 36 x2) =35x(35+63+2) = 35x100=3500