1. a, 3x + |x - 2| = 8
<=> |x - 2| = 8 - 3x
Xét 2 TH :
TH1: x - 2 = 8 - 3x
<=> x + 3x = 8 + 2
<=> 4x = 10
<=> x = \(\dfrac{5}{2}\) (thỏa mãn)
TH2: x - 2 = -(8 - 3x)
<=> x - 2 = -8 + 3x
<=> -2 + 8 = 3x - x
<=> 6 = 2x
<=> x = 3 (thỏa mãn)
b, 5 - |x - 1| = 4
<=> |x - 1| = 1
<=> \(\left[{}\begin{matrix}x-1=1\\x-1=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=0\end{matrix}\right.\) (thỏa mãn)
@Nguyễn Hoàng Vũ

2. 5.(x - 2) - 4.(1 - 3x) = |3 - 7| + 2.(1 + 2x)
<=> 5x - 10 - 4 + 12x = 4 + 2 + 4x
<=> 17x - 14 = 6 + 4x
<=> 17x - 4x = 6 + 14
<=> 13x = 20
<=> x = \(\dfrac{20}{13}\) (thỏa mãn)
@Nguyễn Hoàng Vũ

Bài 1:

\(\left(-\dfrac{72}{40}-\dfrac{144}{60}-2\dfrac{1}{3}\right):\left(\dfrac{45}{100}-\dfrac{25}{60}+-\dfrac{75}{25}\right)\)

\(=\left(-\dfrac{9}{5}-\dfrac{12}{5}-\dfrac{7}{3}\right):\left(\dfrac{9}{20}-\dfrac{5}{12}+-3\right)\)

\(=\left(-\dfrac{27}{15}-\dfrac{36}{15}-\dfrac{21}{15}\right):\left(\dfrac{27}{60}-\dfrac{25}{60}+-3\right)\)

\(=\left(-\dfrac{28}{5}\right):\left(-\dfrac{89}{30}\right)\)

\(=\left(-\dfrac{28}{5}\right).\left(-\dfrac{30}{89}\right)\)

\(=\dfrac{168}{89}\)

\(\left(x+1\right)\left(y-2\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+1=0\\y-2=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0-1\\y=0+2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-1\\y=2\end{cases}}\)

Vậy x = - 1 ; y = 2

\(\Leftrightarrow\dfrac{2}{3}x+\dfrac{4}{3}-\dfrac{5}{4}x+\dfrac{5}{4}=\dfrac{15}{2}-\dfrac{3}{2}x-\dfrac{3}{2}\left(2x+3\right)\)

\(\Leftrightarrow x\cdot\dfrac{-7}{12}+\dfrac{31}{12}=\dfrac{-15}{2}x+3\)

=>83/12x=5/12

hay x=5/83

1: \(\Leftrightarrow x^2-4x+4-2\left(x^2+2x+1\right)=\left(2x+1\right)\left(1-3x\right)+2x\left(x-1\right)\)

\(\Leftrightarrow x^2-4x+4-2x^2-4x-2=\left(2x-6x^2+1-3x\right)+2x^2-2x\)

\(\Leftrightarrow-x^2-8x+2=-6x^2-x+1+2x^2-2x\)

\(\Leftrightarrow-x^2-8x+2=-4x^2-3x+1\)

\(\Leftrightarrow3x^2-5x+1=0\)

\(\Delta=\left(-5\right)^2-4\cdot3\cdot1=25-12=13>0\)

Do đó: Phương trình có hai nghiệm phân biệt là:

\(\left\{{}\begin{matrix}x_1=\dfrac{5-\sqrt{13}}{6}\\x_2=\dfrac{5+\sqrt{13}}{6}\end{matrix}\right.\)

dễ thì tự giải đi

a)x=11

b) x=1

c) x=2

d) x=15

e) x=3

g) x=15

\(C=\frac{5}{2}\cdot\frac{7}{5}\cdot\frac{9}{7}\cdot\frac{11}{9}\cdot...\cdot\frac{2017}{2015}\cdot\frac{2019}{2017}=\frac{2019}{2}\)

\(D=\left(1-\frac{1}{\frac{2\cdot3}{2}}\right)\cdot\left(1-\frac{1}{\frac{3\cdot4}{2}}\right)\cdot\left(1-\frac{1}{\frac{4\cdot5}{2}}\right)\cdot\left(1-\frac{1}{\frac{5\cdot6}{2}}\right)\cdot...\cdot\left(1-\frac{1}{\frac{39\cdot40}{2}}\right)\)

\(=\left(1-\frac{2}{2\cdot3}\right)\cdot\left(1-\frac{2}{3\cdot4}\right)\cdot\left(1-\frac{2}{4\cdot5}\right)\cdot\left(1-\frac{2}{5\cdot6}\right)\cdot...\cdot\left(1-\frac{2}{39\cdot40}\right)\cdot\)

Nhận xét: \(1-\frac{2}{n\left(n+1\right)}=\frac{n\left(n+1\right)-2}{n\left(n+1\right)}=\frac{n^2+n-2}{n\left(n+1\right)}=\frac{\left(n+2\right)\left(n-1\right)}{n\left(n+1\right)}\)nên:

\(D=\frac{4\cdot1}{2\cdot3}\cdot\frac{5\cdot2}{3\cdot4}\cdot\frac{6\cdot3}{4\cdot5}\cdot\frac{7\cdot4}{5\cdot6}\cdot\frac{8\cdot5}{6\cdot7}\cdot...\cdot\frac{41\cdot38}{39\cdot40}=\)

\(D=\frac{4\cdot5\cdot6\cdot7\cdot...\cdot41\times1\cdot2\cdot3\cdot4\cdot...\cdot38}{2\cdot3\cdot4\cdot5\cdot...\cdot39\times3\cdot4\cdot5\cdot6\cdot..\cdot40}=\frac{1}{39}\cdot\frac{41}{3}=\frac{41}{117}\)

`#3107.101107`

`-3^2 + {-54 \div [-2^8 + 7] * (-2)^2}`

`= -9 + [-54 \div (-256 + 7) * 4]`

`= -9 + [-54 \div (-249) * 4]`

`= -9 + (18/83 * 4)`

`= -9 + 72/83`

`= -675/83`

______

`31 * (-18) + 31 * (-81) - 31`

`= 31 * (-18 - 81 - 1)`

`= 31 * (-100)`

`= -3100`

___

`(-12) * 47 + (-12) * 52 + (-12)`

`= (-12) * (47 + 52 + 1)`

`= (-12) * 100`

`= -1200`

___

`13 * (23 + 22) - 3 * (17 + 28)`

`= 13 * 45 - 3 * 45`

`= 45 * (13 - 3)`

`= 45 * 10`

`= 450`

____

`-48 + 48 * (-78) + 48 * (-21)`

`= 48 * (-1 - 78 - 21)`

`= 48 * (-100)`

`= -4800`