Câu hỏi của kiara- Hồ Hách Nhi

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Phương Pham · Accepted Answer

$\left\{{}\begin{matrix}\dfrac{x}{y}-\dfrac{y}{x}=\dfrac{5}{6}\x^2-y^2=5\end{matrix}\right.\ \Leftrightarrow\left\{{}\begin{matrix}6x^2-6y^2=5xy\x^2-y^2=5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}6x^2-6y^2=5xy\6x^2-6y^2=30\end{matrix}\right.\ \Leftrightarrow\left\{{}\begin{matrix}0=5xy-30\6x^2-6y^2=30\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}5xy=30\6x^2-6y^2=30\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{30}{5y}\6\left(\dfrac{30}{5y}\right)^2-6y^2=30\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{30}{5y}\\dfrac{216}{y^2}-6y^2=30\end{matrix}\right.\ \Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{30}{5y}\216-6y^4=30y^2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{30}{5y}\y=2\end{matrix}\right.\ \Leftrightarrow\left\{{}\begin{matrix}x=3\y=2\end{matrix}\right.$Câu trả lời: $\left\{{}\begin{matrix}\dfrac{x}{y}-\dfrac{y}{x}=\dfrac{5}{6}\x^2-y^2=5\end{matrix}\right.\ \Leftrightarrow\left\{{}\begin{matrix}6x^2-6y^2=5xy\x^2-y^2=5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}6x^2-6y^2=5xy\6x^2-6y^2=30\end{matrix}\right.\ \Leftrightarrow\left\{{}\begin{matrix}0=5xy-30\6x^2-6y^2=30\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}5xy=30\6x^2-6y^2=30\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{30}{5y}\6\left(\dfrac{30}{5y}\right)^2-6y^2=30\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{30}{5y}\\dfrac{216}{y^2}-6y^2=30\end{matrix}\right.\ \Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{30}{5y}\216-6y^4=30y^2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{30}{5y}\y=2\end{matrix}\right.\ \Leftrightarrow\left\{{}\begin{matrix}x=3\y=2\end{matrix}\right.$

🍀thiên lam🍀 · Answer

gửi nhầm chỗ b nhé:)Câu trả lời: gửi nhầm chỗ b nhé:)

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