Ta có: \(32^{27}=\left(2^5\right)^{27}=2^{135}\)

\(16^{39}=\left(2^4\right)^{39}=2^{156}\)

mà \(2^{135}< 2^{156}\)

nên \(32^{27}< 16^{39}\)

mà \(16^{39}< 18^{39}\)

nên \(32^{27}< 18^{39}\)

\(\Leftrightarrow-32^{27}>-18^{39}\)

\(\Leftrightarrow\left(-32\right)^{27}>\left(-18\right)^{39}\)

(-32)^27>(-18)^39 nha bn Cá là trong violympic lun

a)>

b)<

mik biết nhưng ko nói

hồ trần nhi nói rứa thì coi như ko biết còn gì nữa

   đúng tick nha!!!!

M = \(\left(1-\frac{1}{2^2}\right)\left(1-\frac{1}{3^2}\right)\left(1-\frac{1}{4^2}\right).....\left(1-\frac{1}{2015^2}\right)\)

M = \(\left(-\frac{1.3}{2.2}\right)\left(-\frac{2.4}{3.3}\right)\left(-\frac{3.5}{4.4}\right)....\left(-\frac{2014.2016}{2015.2015}\right)\)

M = \(\frac{\left(1.2.3....2014\right)\left(3.4.5...2016\right)}{\left(2.3.4.....2015\right)\left(2.3.4....2015\right)}\)

M = \(\frac{2016}{2015.2}\)

M = \(\frac{1008}{2015}\)

N = \(\frac{1}{2}\)=\(\frac{1008}{2016}\)

Vì \(\frac{1008}{2015}>\frac{1008}{2016}\)

=> M > N

Hồ Thu Giang nhầm ở bước thứ hai nhưng ý tưởng tốt                 

a, \(a\in\left\{0,1\right\}\)

b, \(m>n\)

a)Ta có:

 \(\left(\frac{1}{2}\right)^{27}=\left[\left(\frac{1}{2}\right)^3\right]^9=\left(\frac{1}{8}\right)^9\)

\(\left(\frac{1}{3}\right)^{18}=\left[\left(\frac{1}{3}\right)^2\right]^9=\left(\frac{1}{9}\right)^9\)

Vì \(\left(\frac{1}{8}\right)^9>\left(\frac{1}{9}\right)^9\) nên \(\left(\frac{1}{2}\right)^{27}>\left(\frac{1}{3}\right)^{18}\)