= 7/9 + 6/9 + 2/9 + 9/9

= 13/9 + 2/9 + 9/9

= 15/9 + 9/9

= 24/9

= 8/3

\(\frac{7}{9}+\frac{2}{3}+\frac{2}{9}+1\)

\(=\left(\frac{7}{9}+\frac{2}{9}\right)+1+\frac{2}{3}.\)

\(=1+1+\frac{2}{3}.\)

\(=2\frac{2}{3}.\)

Kết quả là 0 nhé ! k mình thì mình giải cho

15*chia hết cho 3 và 5

4

1/4 + 2/5 + 3/7 + 8/5 + 4/7 + 45/60

= (1/4 + 45/60) + (2/5+8/5) + (3/7+4/7)

= (1/4 + 3/4) + 2 + 1

= 1 + 2 + 1 

= 4

a, 23/4 : 3 + 9/4 x 1/3 - 3/8

=  7,8 + 12,22 - 3,8

= 20,02 - 3,8

  =16,22

b, 3/5 : 5/6 : 6/7 : 7/8 + 2/5 +23/35 

=3/5 x 6/5 x 7/6 x 8/7 + 2/5 + 23/35

cảm ơn bn

a; 5\(\dfrac{3}{4}\) : 3 + 2\(\dfrac{1}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)

= \(\dfrac{23}{4}\) : 3 + \(\dfrac{9}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)

= \(\dfrac{23}{4}\) x \(\dfrac{1}{3}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)

= \(\dfrac{23}{12}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)

= \(\dfrac{46}{24}\) + \(\dfrac{18}{24}\) - \(\dfrac{9}{24}\)

= \(\dfrac{64}{24}\) - \(\dfrac{9}{24}\)

= \(\dfrac{55}{24}\)

a: \(x+\dfrac{3}{9}=\dfrac{7}{6}\cdot\dfrac{2}{3}\)

=>\(x+\dfrac{1}{3}=\dfrac{14}{18}=\dfrac{7}{9}\)

=>\(x=\dfrac{7}{9}-\dfrac{1}{3}=\dfrac{7}{9}-\dfrac{3}{9}=\dfrac{4}{9}\)

b: \(x-\dfrac{2}{3}=\dfrac{1}{8}:\dfrac{5}{4}\)

=>\(x-\dfrac{2}{3}=\dfrac{1}{8}\cdot\dfrac{4}{5}=\dfrac{1}{10}\)

=>\(x=\dfrac{1}{10}+\dfrac{2}{3}=\dfrac{3+20}{30}=\dfrac{23}{30}\)

TThế giới oi oi oi 

=2011 do ban

cach giai la 

(1+2-3-4)+(5+6-7-8)+...............+(2005+2006-2007-2008)+2009+2010

=-4+-4+-4+4019

=(-4)x502+4019

=2008+4019

=2011

1, Không ai rảnh để làm cái này ra cho bạn. Mình nghĩ kết quả là 0.

2, Mình không có nick facebook.

Chúc bạn học tốt^^

1a)  x + 2/5 = 1/2 =5/10-4/10=1/10

b=2/7+2/5=10/35+14/35=24/35

=17/6:(1-2/3)

=17/6:1/3

=17/2

=13/6×9/2-6/7

=39/4-6/7

=249/28

a) \(\left(\frac{5}{2}+\frac{1}{3}\right):\left(1-\frac{2}{3}\right)=\left(\frac{15}{6}+\frac{2}{6}\right):\frac{1}{3}\)

\(=\frac{17}{6}:\frac{1}{3}=\frac{17}{6}\cdot\frac{3}{1}=\frac{17}{2}\cdot\frac{1}{1}=\frac{17}{2}\)

b) \(\left(\frac{5}{2}-\frac{1}{3}\right)\cdot\frac{9}{2}-\frac{6}{7}=\left(\frac{15}{6}-\frac{2}{6}\right)\cdot\frac{9}{2}-\frac{6}{7}\)

\(=\frac{13}{6}\cdot\frac{9}{2}-\frac{6}{7}=\frac{13}{2}\cdot\frac{3}{2}-\frac{6}{7}=\frac{39}{4}-\frac{6}{7}=\frac{273}{28}-\frac{24}{28}=\frac{249}{28}\)