(a-b)(c-d)(e-f)x=(b-a)(d-c)(f-e)

=>(a-b)(c-d)(e-f)x = -(a-b)(c-d)(e-f)

=>x=(a-b)(c-d)(e-f)/-(a-b)(c-d)(e-f)=(-1)

x  = 1 nha

Vì a<b=>a-b<0(1)

c<d=>c-d<0(2)

e<f=>e-f<0(3)

từ (1);(2);(3)=>(a-b)(c-d)(e-f)<0 (3)

Vì b>a=>b-a>0(4)

d>c=>d-c>0(5)

f>e=>f-e>0(6)

từ (4);(5);(6)=>(b-a)(d-c)(f-e)>0(7)

từ (3);(7) ta có: (a-b)(c-d)(e-f) là số âm

(b-a)(d-c)(f-e) là số dương

đặt (a-b)(c-d)(e-f)=-S

(b-a)(d-c)(f-e)=S

ta có:(-S).x=S=>x=-1

Vậy x=-1

Thank you :)

-1 nhé bạn

Ta có :

\(\left(a-b\right)\left(c-d\right)\left(e-f\right)x=\left(b-a\right)\left(c-d\right)\left(f-e\right)\)

\(\Leftrightarrow x=\frac{\left(a-b\right)\left(c-d\right)\left(e-f\right)}{\left(b-a\right)\left(c-d\right)\left(f-e\right)}\)

\(\Leftrightarrow x=\left(-1\right)\left(-1\right)\left(-1\right)\)

<=> x = - 1

Vậy ...

x=-1

-1

x=-1 nha bạn

\(\left(a-b\right)\left(c-d\right)\left(e-f\right)x\)

\(=\left(b-a\right)\left(d-c\right)\left(f-e\right)\)

\(\Rightarrow\left(a-b\right)\left(c-d\right)\left(e-f\right)x\)

\(=-\left(a-b\right)\left(c-d\right)\left(e-f\right)\)

\(\Rightarrow x=\frac{\left(a-b\right)\left(c-d\right)\left(e-f\right)}{-\left(a-b\right)\left(c-d\right)\left(e-f\right)}\)

\(\Rightarrow x=-1\)

Vậy \(x=-1\)