\(2^2+10x=\left(2^2.3\right)^2\Leftrightarrow4+10x=2^4.3^2\Leftrightarrow4+10x=144\Leftrightarrow10x=144-4=140\Leftrightarrow x=\frac{140}{10}=14\)Vậy x = 14

2² + 10x = (2².3)²

4 + 10x = (4.3)²

4 + 10x = 144

-> 10x = 140

Vậy x = 14.

Ta có: \(2^2+10.x=\left(2^2.3\right)^2\)

\(\Rightarrow4+10.x=\left(4.3\right)^2=12^2=144\)

\(\Rightarrow10.x=144-4=140\)

\(\Rightarrow x=\frac{140}{10}=14\)

Vậy: \(x=14\)

x = 14

sai đề 

10X=124416^2

X=124416^2/10

=4+10x=144

vậy 10x=144-4

=140

vậy x=140;10=14

= 14 

k nha chúc bạn học giỏi

ta có :

2² +10x=(2².3)²

2² +10x=(4.3)²

4 +10x=12²

4 + 10x = 144

10x = 144 - 4

10x = 140

x = 140 : 10

x = 14

2² + 10x = ( 2² . 3 )²

2² + 10x = 2⁴ . 3²

4 + 10x  = 16 . 9

4 + 10x  = 144

       10x = 144 - 4

        10x = 140

            x = 140 : 10

            x = 14

\(10x+10y=10\left(x+y\right)=10.\left(-2\right)=-20\)

Q=10(x+y)=-2x10=-20

a) \(A=x^2-10x+5\)

\(A=x^2-10x+25-20\)

\(A=\left(x-5\right)^2-20\ge-20\)

Min A = -20 \(\Leftrightarrow x=5\)

b) \(B=3x^2-6x+11\)

\(B=3\left(x^2-2x+1\right)+8\)

\(B=3\left(x-1\right)^2+8\ge8\)

Min B = 8\(\Leftrightarrow x=1\)

a) \(A=x^2-10x+5=\left(x^2-10x+25\right)-20\)

\(=\left(x-5\right)^2-20\ge-20\left(\forall x\right)\)

Dấu "=" xảy ra khi: \(\left(x-5\right)^2=0\Rightarrow x=5\)

Vậy \(Min_A=-20\Leftrightarrow x=5\)

b) \(B=3x^2-6x+11=3\left(x^2-2x+1\right)+8\)

\(=3\left(x-1\right)^2+8\ge8\left(\forall x\right)\)

Dấu "=" xảy ra khi: \(\left(x-1\right)^2=0\Rightarrow x=1\)

Vậy \(Min_B=8\Leftrightarrow x=1\)

c) \(C=8x^2+10x-30=8\left(x^2-\frac{5}{4}x+\frac{25}{64}\right)-\frac{265}{8}\)

\(=8\left(x-\frac{5}{8}\right)^2-\frac{265}{8}\ge-\frac{265}{8}\)

Dấu "=" xảy ra khi: \(\left(x-\frac{5}{8}\right)^2=0\Rightarrow x=\frac{5}{8}\)

Vậy \(Min_C=-\frac{265}{8}\Leftrightarrow x=\frac{5}{8}\)

khó lắm:))