tìm giá trị của biểu thức sau

a) 45 mũ 10 . 5 mũ 20 / 75 mũ 15

b) (0,8) mũ 5 / (0,4) mũ 6

c) 2 mũ 15 . 9 mũ 4 / 6 mũ 6 . 8 mũ 3

bài làm là:

a) 45^10.5^20/75 ^ 15

=(5.9)^10.5^20/(5.15)^15

=5^10.9^10.5^20/5^15.15^15

=5^30.3^20/5^15.3^15.5^15

=5^30.3^20/5^30.3^15

=5^30.3^20/5^30.3^15

=3^5

=243

mấy ý kia mình chia tính được ....A,hihi

A= (9¹⁰.5¹⁰​.5¹⁰​)/(25¹⁰​.3^​10)=(3^​20​.5²⁰​)/(5^​20.3^​10)=3^​10

​B=(0,8)^​5/(0,4)⁶= (2.0,4)⁵​/0,4.0,4⁵ ​= 2⁵.0,4⁵/0,4.0,4⁵ = 2^​5​/0,4 = 80

​C= 2¹⁵.9⁴​/6^​6.8³= 2_​^​15​.3⁸​/3⁶.2⁶.2⁹=2^​15.3⁸/3⁶.2^​15=3²=9

bo deo quantam

45^10 x 5^20 / 75^15

= ( 3^2 x 5)^10 x 5^20 / ( 3 x 5^2)^15

= 3^20 x 5^10 x 5^20 / 3^15 x 5^30

= 3^5

= 243

p/s : theo mk thì lm như vậy đó

1/3^15

1) \(\dfrac{5}{10}=\dfrac{5:5}{10:5}=\dfrac{1}{2}\)

\(\dfrac{-18}{-27}=\dfrac{-18:\left(-9\right)}{-27:\left(-9\right)}=\dfrac{2}{3}\)

\(\dfrac{-42}{105}=\dfrac{-42:21}{105:21}=\dfrac{-2}{5}\)

\(\dfrac{75}{-135}=\dfrac{75:\left(-15\right)}{-135:\left(-15\right)}=\dfrac{-5}{9}\)

\(\dfrac5{10}=\dfrac{5.1}{5.2}=\dfrac12\\\dfrac{-18}{-27}=\dfrac{(-9).2}{(-9).3}=\dfrac23\\\dfrac{-42}{105}=\dfrac{21.(-2)}{21.5}=\dfrac{-2}5\\\dfrac{75}{-135}=\dfrac{(-15).(-5)}{(-15).9}=\dfrac{-5}9\)

a) Đặt: A = \(\frac{5.7^{12}}{7^{10}.5^{10}}=\frac{5.7^2.7^{10}}{7^{10}.5^{10}}=\frac{7^2}{5^9}\)

b) Đặt: B = \(\frac{5^8.7^{12}-5^9.7^{11}}{7^{11}.5^{10}+7^{12}.5^{11}}=\frac{5^8.7.7^{11}-5.5^8.7^{11}}{7^{11}.5^{10}+7.7^{11}.5.5^{10}}\\ =\frac{5^8.7^{11}.\left(7-5\right)}{7^{11}.5^{10}.\left(1+7.5\right)}=\frac{2}{5^2.36}=\frac{2}{25.36}=\frac{1}{450}\)

a)\(\frac{5.7^{12}}{7^{10}.5^{10}}=\frac{5.7^{10}.7^2}{7^{10}.5.5^9}=\frac{7^2}{5^9}\)