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Ta có A = 5 + 52 + 53 + ... + 52021
5A = 52 + 53 + 54 + ... + 52022
5A - A = ( 52 + 53 + 54 + ... + 52022 ) - ( 5 + 52 + 53 + ... + 52021 )
4A = 52022 - 5
A = \(\dfrac{5^{2022}-5}{4}\)
Tìm chữ số tận cùng của kết quả mỗi phép tính sau:
a. 4915
b. 5410
c. 1120+11921+200022
\(\dfrac{14}{21}=\dfrac{7\cdot2}{7\cdot3}=\dfrac{2}{3}\)
\(\dfrac{-36}{48}=\dfrac{-12\cdot3}{12\cdot4}=-\dfrac{3}{4}\)
\(\dfrac{28}{-52}=\dfrac{7\cdot4}{-4\cdot13}=-\dfrac{7}{13}\)
\(\dfrac{-54}{-90}=\dfrac{-18\cdot3}{-18\cdot5}=\dfrac{3}{5}\)
\(\dfrac{14}{21}\) =\(\dfrac{2}{3}\)
\(\dfrac{-36}{48}\) =\(\dfrac{3}{4}\)
\(\dfrac{28}{-52}\)=\(\dfrac{7}{-13}\)
\(\dfrac{-54}{-90}\) =\(\dfrac{6}{9}=\dfrac{2}{3}\)
a) \(7^3.7^5=7^{3+5}=7^8\)
b)\(5^6.5^4=5^{6+4}=5^{10}\)
14/21=2/3; -36/48=-2/3
28/-52=-7/13; -54/-90=3/5
-21/39=-7/13
-21/39=-7/13=-14/26=-21/39=-28/52=-35/65=-42/78=-48/91
`14/21=2/3`
`(-36)/48=-3/4`
`28/(-52)=-7/13`
`(-54)/(-90)=3/5`
`(-21)/39=-7/13`
Lời giải:
$C=1+5+5^2+5^4+.....+5^{98}+5^{100}$
$25C=5^2C=5^2+5^3+5^4+5^6+....+5^{100}+5^{102}$
$25C-C=(5^3+5^{102})-(5+1)$
$24C=5^{102}-119$
$C=\frac{5^{102}-119}{24}$
a: \(12+2^2+3^2+4^2+5^2\)
\(=12+4+9+16+25\)
\(=16+50=66\)
\(\left(1+2+3+4+5\right)^2=15^2=225\)
=>\(12+2^2+3^2+4^2+5^2< \left(1+2+3+4+5\right)^2\)
b: \(1^3+2^3+3^3+4^3=\left(1+2+3+4\right)^2< \left(1+2+3+4\right)^3\)
c: \(5^{202}=5^2\cdot5^{200}=25\cdot5^{200}>16\cdot5^{200}\)
d: \(18\cdot4^{500}=18\cdot2^{1000}\)
\(2^{1004}=2^4\cdot2^{1000}=16\cdot2^{1000}\)
=>\(18\cdot4^{500}>2^{1004}\)
e: \(2022\cdot2023^{2024}+2023^{2024}=2023^{2024}\left(2022+1\right)\)
\(=2023^{2025}\)
Bài 1:
$B=1+3+3^2+3^3+...+3^{100}$
$=1+(3+3^2)+(3^3+3^4)+...+(3^{99}+3^{100})$
$=1+3(1+3)+3^3(1+3)+...+3^{99}(1+3)$
$=1+(1+3)(3+3^3+...+3^{99})=1+4(3+3^3+....+3^{99})$
$\Rightarrow B$ chia 4 dư 1.
Bài 2:
$C=5-5^2+5^3-5^4+...+5^{2023}-5^{2024}$
$5C=5^2-5^3+5^4-5^5+...+5^{2024}-5^{2025}$
$\Rightarrow C+5C=5-5^{2025}$
$6C=5-5^{2025}$
$C=\frac{5-5^{2025}}{6}$
18,34+(-18)x124=18,34+-2232
=2213,66
-36,17+9 x-52= -36,17+468
=431,83
tử số =18.123+9.4567.2+3.5310.6=18.123+18.4567+18.5310
=18(123+4567+5310)
=18.10000=180000
mẫu số = 1+4+7+....+49+52+55+58-490
=(1+58)+(4+55)+.....(28+31)-490
=59+59+59+...+59-490(10 so 59)
=100
suy ra A=180000:100=1800
\(A=\left(1+5^2+5^4+...+5^{200}\right)\)
=>\(5^2.A=5^2.\left(1+5^2+5^4+...+5^{200}\right)\)
=>\(25A=5^2+5^4+5^8+...+5^{202}\)
=>\(25A-A=\left(5^2+5^4+5^6+...+5^{202}\right)-\left(1+5^2+5^4+...+5^{200}\right)\)
=>\(24A=5^{202}-1\Rightarrow A=\frac{5^{202}-1}{24}\)