a, 2x + 12= 3(x - 7)

=> 2x + 12 = 3x + 21

=> 12 - 21 = 3x - 2x

=> -9 = x

vậy x = -9

b,-2x-(-17)=15

=> -2x + 17 = 15

=> -2x = 32

=> x = -16

Bài 2

a, A=(-a-b-c)-(-a-b-c)

= -a - b - c + a + b + c 

= 0

b, thay vào thì nó vẫn = 0 thôi

Bài 2: 

a: =a-b+c+a-c+b-b

=2a-b

b: =2x-5+x-a+x-5-a

=4x-10-2a

Hả 2+b - b+ 10 là 3c há

GIÚP MK VỚI HU HU

Bài 1:

a) 

<=> 3x - 18 - 5x + 10 = 24

<=>   3x - 5x              = 24 + 18 - 10

<=>     -2x                  = 32

<=>     x                     = 32 : (-2)

<=>     x                     = -16

b)

<=> -4x + 20 - 8x + 16 = 48

<=> -4x - 8x                 = 48 - 20 - 16

<=>  -12x                     = 12

<=>      x                       = 12 : (-12)

<=>      x                       = -1

Bài 2:

\(=a^2-ab+ab-b^2\)

\(=a^2-b^2\)

a) 3(x-6)-5(x-2) = 24

<=> 3x -36 -5x + 10 =24

<=> -2x = 50

<=> x = -25

b) -4(x-5) -8(x-2) = 48

<=> -4x +20 - 8x +16 = 48

<=> -12x = 12

<=> x = -1

(a+b)(a-b) = a^2 -ab +ab -b^2 = a^2 - b^2

a, A=(a-b)-(a-b+c)

     =a-b-a+b-c

     =(a-a)+(b-b)-c

     = 0 + 0 - c

     =-c

b, B=(a+b+c)-(a+b-c)

    =a+b+c-a-b+c

   =(a-a)+(b-b)+(c+c)

   =0+0+2c

  =2c

t**k cho mình nha!!

chúc hok tốt!!

a)   \(A=\left(a-b\right)-\left(a-b+c\right)\)

\(=a-b-a+b-c\)

\(=\left(a-a\right)+\left(b-b\right)-c\)  \(=-c\)

b)   \(B=\left(a+b+c\right)-\left(a+b-c\right)\)

\(=a+b+c-a-b+c\)

\(=\left(a-a\right)+\left(b-b\right)+\left(c+c\right)\)

\(=2c\)

X+21+(-18)+(-40)=x+21-18-40=x-37

-55-(y+

a) x + 21 + (-18) + (-40)

= x + 21 - 18 - 40

= x - 37

b) -55 - (y + 20) - (-55)

= -55 -y - 20 + 55

= - y - 20

c) -(a - b) + ( a - c -d + b )

= - a + b + a -c - d +b 

= 2b - c - d

\(a,-\frac{9}{12}=-\frac{9:3}{12:3}=-\frac{3}{4}\)

\(\frac{-18}{-24}=\frac{\left(-18\right):\left(-6\right)}{\left(-24\right):\left(-6\right)}=\frac{3}{4}\)

\(-\frac{35}{70}=-\frac{35:35}{70:35}=\frac{1}{2}\)

\(-\frac{9}{27}=-\frac{9:9}{27:9}=-\frac{1}{3}\)

\(b,\frac{1313}{4242}=\frac{1313:101}{4242:101}=\frac{13}{42}\)

\(\frac{-353535}{-424242}=\frac{\left(-353535\right):\left(-70707\right)}{\left(-424242\right):\left(-70707\right)}=\frac{5}{6}\)

\(c,\frac{2^3\times4^3\times5^4}{8^2\times25^3\times7}=\frac{2^3\times4^3\times25^2}{8\times8^2\times25^2\times25\times7}\)         ( 4^3 = 8^2 ; 5^4 = 25^2 )

\(=\frac{1}{25\times7}=\frac{1}{175}\)

\(a.\frac{-9}{-12}=\frac{-9:3}{-12:3}=\frac{-3}{-4}.\)

\(\frac{-18}{-24}=\frac{-18:6}{-24:6}=\frac{-3}{-4}\)

\(\frac{-35}{-70}=\frac{-35:35}{-70:35}=\frac{-1}{-2}\)

\(\frac{-9}{-27}=\frac{-9:9}{-27:9}=\frac{-1}{-3}\)