Bài 2: 

a: Ta có: \(\dfrac{9}{11}=1-\dfrac{2}{11}\)

\(\dfrac{13}{15}=1-\dfrac{2}{15}\)

mà \(-\dfrac{2}{11}< -\dfrac{2}{15}\)

nên \(\dfrac{9}{11}< \dfrac{13}{15}\)

b: Ta có: \(\dfrac{19}{15}=1+\dfrac{4}{15}\)

\(\dfrac{15}{11}=1+\dfrac{4}{11}\)

mà \(\dfrac{4}{15}< \dfrac{4}{11}\)

nên \(\dfrac{19}{15}< \dfrac{15}{11}\)

2 câu kia đâu rùi

a: 9/11=1-2/11

11/13=1-2/13

mà -2/11<-2/13

nên 9/11<11/13

b: 19/15=1+4/15

15/11=1+4/11

mà 4/15<4/11

nên 19/15<15/11

còn câu c,d

21/35=3/5; 12/20=3/5

=>21/35=12/20

24/35<1<21/7

35/49=5/7; 40/64=5/8

=>35/49>40/64

2424/4848=1/2

9/11=1-2/11

13/15=1-2/15

mà 2/11>2/15

nên 9/11<13/15

19/15>11/15

khó

a) Ta có:

\(1-\frac{9}{11}=\frac{11-9}{11}=\frac{2}{11}\)

\(1-\frac{13}{15}=\frac{15-13}{15}=\frac{2}{15}\)

Vì \(\frac{2}{15}< \frac{2}{11}\Rightarrow1-\frac{9}{11}< 1-\frac{13}{15}\Rightarrow\frac{9}{11}>\frac{13}{15}\)

b) Ta có

\(\frac{201}{301}>\frac{201}{308}>\frac{199}{308}\Rightarrow\frac{201}{301}>\frac{199}{308}\)

\(1.\frac{13}{40}=\frac{8}{40}+\frac{5}{40}=\frac{1}{5}+\frac{1}{8}\)          2.Ta có : \(\frac{427}{512}<\frac{472}{512}<\frac{472}{501}\Rightarrow\frac{427}{512}<\frac{472}{501}\)

3. Đáp án a.

tốn chỗ thế

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