\(2^{150}=\left(2^5\right)^{30}=32^{30}\)(1)

\(3^{90}=\left(3^3\right)^{30}=27^{30}\)(2)

Từ (1),(2)=>\(2^{150}>3^{90}\) hay \(32^{30}>27^{30}\)

\(2^{150}=\left(2^5\right)^{30}=32^{30}\)

\(3^{90}=\left(3^3\right)^{30}=27^{30}\)

mà 32>27

nên \(2^{150}>3^{90}\)

1,10²⁰và 90¹⁰

ta có:+,10²⁰=(10²)¹⁰=100¹⁰

        +,90¹⁰=90¹⁰

vì 100¹⁰>90¹⁰=>10²⁰>90¹⁰

2,(1/16)¹⁰ và (1/2)⁵⁰

ta có:+, (1/16)¹⁰=(1/16)¹⁰

         +,(1/2)⁵⁰=(1/2⁵)¹⁰=(1/32)¹⁰

vì (1/16)¹⁰>(1/32)¹⁰=>(1/16)¹⁰>(1/2)⁵⁰

k mik nhé

\(a,\)  \(10^{20}=10^{10+10}=10^{10}.10^{10}\)

        \(90^{10}=9^{10}.10^{10}\)

  Vì \(10^{10}.10^{10}>9^{10}.10^{10}\)

    \(\Rightarrow10^{20}>90^{10}\)

Vậy \(10^{20}>90^{10}\)

\(b,\)\(\left(\frac{1}{16}\right)^{10}=\frac{1^{10}}{16^{10}}=\frac{1}{\left(4^2\right)^{10}}=\frac{1}{4^{20}}\)

   \(\left(\frac{1}{2}\right)^{50}=\frac{1^{50}}{2^{50}}=\frac{1}{\left(2^2\right)^{25}}=\frac{1}{4^{25}}\)

Vì \(\frac{1}{4^{20}}>\frac{1}{4^{25}}\)

\(\Rightarrow\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)

Vậy \(\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)

                         ~~~~~~~~~~Hok tốt~~~~~~~~~~~

Có: \(^{9^{36}}\)=\(^{\left(3^2\right)^{36}}\)=\(3^{72}\)

       \(27^{10}\)=\(\left(3^3\right)^{10}\)=\(3^{30}\)

Vì 3 mũ 72 > 3 mũ 30 suy ra 9 mũ 36 > 27 mũ 10

9^36=(3^3)^36=3^108

27^10=(3^9)^10=3^90

Suy ra 9^36>27^10

Ta có :

5²⁷  = ( 5³ )⁹ = 125⁹ < 128⁹ = ( 2⁷ )⁹ = 2⁶³

=> 5²⁷ < 2⁶³

Mà 2⁶³ < 2⁶⁴ = ( 2¹⁶ )⁴ = 65536⁴ < 5²⁸ = ( 5⁷ )⁴ = 78125⁴ 

=> 5²⁷ < 2⁶³ < 5²⁸

\(5^{27}< 5^{28}< 5^{63}\)

b: \(2^{27}=8^9\)

\(3^{18}=9^9\)

mình đang cần gâps

625⁵ và 125⁷

a, 625⁵ = (5⁴)⁵ = 5²⁰

125⁷ = (5³)⁷ = 5²¹

Vì 5²⁰ < 5²¹ nên 625⁵ < 125⁷

b,  3²ⁿ = (3²)ⁿ = 9ⁿ

     2³ⁿ = (2³)ⁿ = 8ⁿ

     9ⁿ > 8ⁿ ( nếu n > 0)

      9ⁿ = 8ⁿ (nếu n = 0)

Vậy nếu n = 0 thì 2³ⁿ = 3²ⁿ
      nếu n > 0 thì 3²ⁿ > 2³ⁿ