KO PHẢI CÂU NÀY NHÉ MÀ LÀ CÂU dưới này

Thu gọn các đơn thức trong biểu thức đại số sau:

D = (3x4y4)2.(116x3y).(8xn−7).(−2x7−n)15x3y2.(0,4ax2y2z2)2 ( với axyz khác 0)

\(C=\frac{7}{9}x^3y^2\left(\frac{6}{11}axy^3\right)+\left(-5bx^2y^4\right)\left(\frac{-1}{2}axz\right)+ax\left(x^2y\right)^3\)

\(\Rightarrow C=\frac{42}{9}ax^4y^5+\frac{5}{2}abx^3y^4z+ax\left(x^6y^3\right)\)

\(\Rightarrow C=\frac{42}{9}ax^4y^5+\frac{5}{2}abx^3y^4z+ax^7y^3\)

\(D=\frac{\left(3x^4y^4\right)^2\left(\frac{6}{11}x^3y\right)\left(8x^{n-7}\right)\left(-2x^{7-n}\right)}{15x^3y^2\left(0,4ax^2y^2z^2\right)^2}\)

\(D=\frac{\left[3.\frac{6}{11}.8.\left(-2\right)\right]\left(x^8x^3x^{n-7}x^{7-n}\right)\left(y^8y\right)}{15.0,4.\left(x^3x^4\right)\left(y^2y^4\right)z^4a}\)

\(D=\frac{\frac{-188}{11}x^{24}y^9}{6x^7y^6z^4a}\)

\(D=\dfrac{9x^8y^6\cdot\dfrac{1}{6}x^2y-16\cdot x^{n-9+9-n}}{6ax^5y^4z^2}\)

\(=\dfrac{\dfrac{3}{2}x^{10}y^7-16}{6ax^5y^4z^2}\)

\(D=\dfrac{\left(3x^4y^4\right)^2\cdot\left(\dfrac{1}{16}x^3y\right)\cdot\left(8x^{n-7}\right)\cdot\left(-2x^{7-n}\right)}{15x^3y^2\cdot\left(0,4ax^2y^2z^2\right)^2}\)

\(=\dfrac{\left(3x^8y^8\right)\cdot\left(\dfrac{1}{16}x^3y\right)\cdot\left(8x^n:x^7\right)\cdot\left(-2x^7:x^n\right)}{15x^3y^2\cdot0,16a^2x^4y^4z^4}\)

\(=\dfrac{\left[3\cdot\dfrac{1}{16}\cdot8\cdot\left(-2\right)\right]\left[x^8\cdot x^3\left(x^7:x^7\right)\left(x^n:x^n\right)\right]\left(y^8y\right)}{\left(15\cdot0,16\cdot a^2\right)\left(x^3x^4\right)\left(y^2y^4\right)z^4}\)

\(=\dfrac{-3x^{11}y^9}{2,4a^2x^7y^6z^4}=\dfrac{-3x^4y^3}{2,4a^2z^4}\)

nếu muốn rút gọn nốt -3 vs 2,4 thì bn tự rút gọn nhé!

\(A=x^3.\left(-\dfrac{5}{4}x^2y\right).\left(\dfrac{2}{5}x^3y^4\right).\\ A=-\dfrac{1}{2}x^8y^5.\)

- Bậc: 8.

- Hệ số: \(-\dfrac{1}{2}.\)

- Biến: \(x;y.\)

\(B=\left(-\dfrac{3}{4}x^5y^4\right).\left(xy^2\right).\left(-\dfrac{8}{9}x^2y^3\right).\\ B=\dfrac{2}{3}x^8y^9.\)

- Bậc: 9.

- Hệ số: \(\dfrac{2}{3}.\)

- Biến: \(x;y.\)