a)(7.3^5-3^4+3^6):3^4 (7.(3^5=243)-(3^4=81)+(3^6=729)):(3^4=81)=29

b)(16^3-64^2):8^2 ((16^3=4096)-(64^2=4096)):(8^2=64)=0

c)(3x^2y^2+6y^2):3y lấy 3x^2y^2:3y=x^2y rồi lấy 6y^2:3y=2y cộng 2 kết quả lạ

a)(7.243-81+729):81=29

b)(4096-4096):64=0

c)(9x^2.3x^2y+36y^2):3y=3x^2y+12y

Bài 3:

3: \(6x\left(x-y\right)-9y^2+9xy\)

\(=6x\left(x-y\right)+9xy-9y^2\)

\(=6x\left(x-y\right)+9y\left(x-y\right)\)

\(=\left(x-y\right)\left(6x+9y\right)\)

\(=3\left(2x+3y\right)\left(x-y\right)\)

Bài 4:

a,=x^2+2x

c,=x^2-1

f: \(=\dfrac{2x^3-10x^2-11x^2+55x+12x-60}{x-5}=2x^2-11x+12\)

Bài 44: (SBT/12):

a. (7.3⁵ - 3⁴ + 3⁶) : 3⁴

= (7.3⁵ : 3⁴) + (-3⁴ : 3⁴) + (3⁶ : 3⁴)

= 7 . 3 - 1 + 3²

= 21 - 1 + 9

= 29

b. (16³ - 64²) : 8³

= [(2.8)³ - (8²)² ] : 8³

= (2³ . 8³ - 8⁴) : 8³

= ( 2³ . 8³ : 8³) + (-8⁴ : 8³)

= 2³ - 8

= 8 - 8

= 0

a) \(\left(7.3^5-3^4+3^6\right):3^4\)

\(=7.3^5:3^4-3^4:3^4+3^6:3^4\)

\(=7.3^{5-4}-3^{4-4}+3^{6-4}\)

\(=7.3^1-3^0+3^2\)

\(=7.3-1+9\)

\(=21-1+9\)

\(=20+9\)

\(=29\)

b) \(\left(16^3-64^2\right):8^3\)

\(=\left[\left(2^4\right)^3-\left(2^6\right)^2\right]:\left(2^3\right)^3\)

\(=\left(2^{4.3}-2^{6.3}\right):2^{3.3}\)

\(=\left(2^{12}-2^{12}\right):2^9\)

\(=2^{12-9}-2^{12-9}\)

\(=2^3-2^3\)

\(=8-8\)

\(=0\)

\(a,-2xy^2\left(x^3y-2x^2y^2+5xy^3\right)\\ =-2x^4y^3+4x^3y^4-10x^2y^5\\ b,\left(-2x\right)\left(x^3-3x^2-x+1\right)\\ =-2x^4+6x^3+2x^2-2x\\ c,\left(-10x^3+\dfrac{2}{5}y-\dfrac{1}{3}z\right)\left(-\dfrac{1}{2}zy\right)\\ =5x^3yz-\dfrac{1}{5}y^2z+\dfrac{1}{6}yz^2\\ d,3x^2\left(2x^3-x+5\right)=6x^5-3x^3+15x^2\\ e,\left(4xy+3y-5x\right)x^2y=4x^3y^2+3x^2y^2-5x^3y\\ f,\left(3x^2y-6xy+9x\right)\left(-\dfrac{4}{3}xy\right)\\ =-4x^3y^2+8x^2y^2-12x^2y\)

a: =-4xyz^2

b: =-9x^2y

c: =16x^2y^2

d: =1/6x^2y^3

e: =13/6x^3y^2

f: =7/12x^4y

a) -xyz² - 3xz.yz

= -xyz² - 3xyz²

= -4xyz²

b) -8x²y - x.(xy)

= -8x²y - x²y

= -9x²y

c) 4xy².x - (-12x²y²)

= 4x²y² + 12x²y²

= 16x²y²

d) 1/2 x²y³ - 1/3 x²y.y²

= 1/2 x²y³ - 1/3 x²y³

= 1/6 x²y³

e) 3xy(x²y) - 5/6 x³y²

= 3x³y² - 5/6 x³y²

= 13/6 x³y²

f) 3/4 x⁴y - 1/6 xy.x³

= 3/4 x⁴y - 1/6 x⁴y

= 7/12 x⁴y

sau bạn đăng tách ra cho mn cùng giúp nhé 

a, \(\left(-2x^5+3x^2-4x^3\right):2x^2=-x^3+\frac{3}{2}-2x\)

b, \(\left(x^3-2x^2y+3xy^2\right):\left(-\frac{1}{2}x\right)=-\frac{x^2}{2}+xy-\frac{3y^2}{2}\)

c, \(\left(3x^2y^2+6x^3y^3-12xy^2\right):3xy=xy+2x^2y^2-4y\)

d, \(\left(4x^3-3x^2y+5xy^2\right):\frac{1}{2}x=2x^2-\frac{3xy}{2}+\frac{5y^2}{2}\)

e, \(\left(18x^3y^5-9x^2y^2+6xy^2\right):3xy^2=6x^2y^3-3x+2\)

f, \(\left(x^4+2x^2y^2+y^4\right):\left(x^2+y^2\right)=\left(x^2+y^2\right)^2:\left(x^2+y^2\right)=x^2+y^2\)