a: \(\dfrac{3}{7}\cdot\dfrac{14}{5}=\dfrac{3}{5}\cdot\dfrac{14}{7}=\dfrac{3}{5}\cdot2=\dfrac{6}{5}\)

b: \(\dfrac{35}{9}\cdot\dfrac{81}{7}=\dfrac{81}{9}\cdot\dfrac{35}{7}=5\cdot9=45\)

c: \(\dfrac{28}{17}\cdot\dfrac{68}{14}=\dfrac{68}{17}\cdot\dfrac{28}{14}=4\cdot2=8\)

d: \(\dfrac{35}{46}\cdot\dfrac{23}{105}=\dfrac{35}{105}\cdot\dfrac{23}{46}=\dfrac{1}{2}\cdot\dfrac{1}{3}=\dfrac{1}{6}\)

e: \(\dfrac{12}{5}\cdot\dfrac{10}{18}=\dfrac{12}{18}\cdot\dfrac{10}{5}=\dfrac{2}{3}\cdot2=\dfrac{4}{3}\)

f: \(\dfrac{15}{4}\cdot\dfrac{8}{10}=\dfrac{15}{10}\cdot\dfrac{8}{4}=\dfrac{3}{2}\cdot2=3\)

a) \(\dfrac{3}{7}\cdot\dfrac{14}{5}=\dfrac{3\cdot14}{7\cdot5}=\dfrac{3\cdot2}{5}=\dfrac{6}{5}\)

b) \(\dfrac{35}{9}\cdot\dfrac{81}{7}=\dfrac{35\cdot81}{9\cdot7}=5\cdot9=45\)

c) \(\dfrac{28}{17}\cdot\dfrac{68}{14}=\dfrac{28\cdot68}{17\cdot14}=2\cdot4=8\)

d) \(\dfrac{35}{46}\cdot\dfrac{23}{105}=\dfrac{35}{105}\cdot\dfrac{23}{46}=\dfrac{1}{3}\cdot\dfrac{1}{2}=\dfrac{1}{6}\) 

e) \(\dfrac{12}{5}\cdot\dfrac{10}{18}=\dfrac{12}{5}\cdot\dfrac{5}{9}=\dfrac{12}{9}=\dfrac{4}{3}\)

f) \(\dfrac{15}{4}\cdot\dfrac{8}{10}=\dfrac{15\cdot8}{4\cdot10}=\dfrac{3\cdot2}{2}=3\)

làm ơn đi mik t cho 

mình xin lỗi mình ko giỏi bài này cho lắm

a) \(\left( { - 12,5} \right).1,2 =  - \left( {12,5.1,2} \right) =  - 15\)

b) \(\left( { - 12,5} \right).\left( { - 1,2} \right) = 12,5.1,2 = 15\)

1) a) (-12).12 = -(12.12) = -144      

    b) 137.(-15) = -(137.15) = - 2 055

2) 5.(-12) = -(5.12) = -60

\(6^{4^{10}}.\left(3^{35}\right)^4\) = 6^(...6) . 3^35.4 = (...6) . (3⁴)³⁵ = (....6) . (...1)³⁵ = (...6) . (...1) = (.....1)

Vậy chữ số tận cùng của phép tính là 1

Hồ Thu Giang làm nhanh quá

a: \(\dfrac{1\cdot5\cdot6+2\cdot10\cdot12}{1\cdot3\cdot52\cdot6\cdot10}=\dfrac{5\cdot6\left(1+2\cdot2\cdot2\right)}{3\cdot52\cdot6\cdot10}\)

\(=\dfrac{1}{2}\cdot\dfrac{9}{156}\)

\(=\dfrac{9}{312}=\dfrac{3}{104}\)

bạn làm lại mình ghi sai đề

a)

\(\left( { + 3} \right)\left( { + 4} \right) = 3.4 = 12\)

\(\left( { + 5} \right).\left( { + 2} \right) = 5.2 = 10\)

b)

Các tích liên tiếp tăng 5 đơn vị nên \(\left( { - 1} \right).\left( { - 5} \right) = 5\) và đến tích cuối cùng là \(\left( { - 2} \right).\left( { - 5} \right) = 10\).

144

2055

\(\left(-12\right).\left(-12\right)=144\)

\(\left(-137\right).\left(-15\right)=2055\)

a) (-12).(-12) = 12.12 = 144          

b) (-137) (-15) = 137.15 = 2055.