a) 81^11.3^17/27^10.9^15

=(9^2)^11.3^17/(3^3)^10.9^15

=3^44.3^17/3^30.3^30

=3^61/3^60

=3

b) A =( (2^12.3^5 - 2^12.3^4)/ (2^12.3^6 + 2^12.3^5) ) - ((5^10.7^3 - 5^10.7^4)/(5^9.7^3 + 5^9.2^3.7^3))

=(2^12.3^4(3-1))/2^12.3^5(3+1) - 5^10.7^3(1-7)/5^9.7^3(1+8)

=2/12- (-30/9)=1/6 + 10/3 = 7/2

3/6, /8,4/6

ý bạn là nhân đa thức với đa thức hay sao ạ?

a. M=-1^2+2^2-3^2+4^2-...-99^2+100^2.

M=(2-1)(2+1)+(4-3)(4+3)+...+(100-99)(100+99)

M=3+7+...+199

=>2M=3+7+...+199+3+7+...+199 (198 số)

=(3+199)+(7+195)+...+(199+3)   (99 cặp)

=202.99

=19998

=>M=19998:2=9999

a) 2x^2 + 3( x-1)(x+1) - 5x(x+1)

= 2x^2 + 3( x^2 -1 ) - 5x(x+1)

= 2x^2 + 3x^2 - 3 - 5x^2 - 5x

= -5x -3 

`8x^4y^5z^3 : 2x^3y^4z`

`= 4xyz^2`.

\(\frac{1+2.3^6}{2^3.3^6-2^3.5^3}-\frac{1+3^6}{8\left(9^3-125\right)}-\frac{5^3}{18^3-10^3}\)

\(=\frac{1+2.3^6}{2^3\left(3^6-5^5\right)}-\frac{1+3^6}{2^3\left[\left(3^2\right)^3-5^3\right]}-\frac{5^3}{\left(2.3^2\right)^3-\left(2.5\right)^3}\)

\(=\frac{1+2.3^6}{2^3\left(3^6-5^3\right)}-\frac{1+3^6}{2^3\left(3^6-5^3\right)}-\frac{5^3}{2^3\left(3^6-5^3\right)}\)

\(=\frac{\left(1+2.3^6\right)-\left(1+3^6\right)-5^3}{2^3\left(3^6-5^2\right)}\)

\(=\frac{3^6-5^3}{2^3\left(3^6-5^3\right)}\)

\(=\frac{1}{8}\)