A=0 Hình như thế

Ak chắc chắn

$B=636363\cdot37-373737\cdot63$

$=63\cdot10101\cdot37-37\cdot10101\cdot63$

$=0$

ưeqfrety6yhythythyt

B=47/41.[12.(1+1/19-1/37-1/53)/3.(1+1/19-1/37-1/53):4.(1+1/17+1/19+1/2006)/5.(1+1/17+1/19+1/2006)].123/235

=47/41.[4:4/5].123/235

=47/41.5.123/235=3

C=63.10101.37-37.10101.63/1+2+3+...+2006

=0/1+2+3+...+2006=0

CẬU XEM LẠI CHO MÌNH NHA!

\(\frac{636363.37-373737.63}{1+2+3+...+2006}=\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}=\frac{0}{1+2+3+...+2006}=0\)

Mình đảm bảo đúng 100%

kết quả = 0 nha bn, vì tử số có kết quả bằng 0 ^^

\(\frac{636363.37-373737.63}{1+2+3+4+...+2006}=\frac{63.10101.37-37.10101.63}{1+2+3+4+...+2006}=\frac{0}{1+2+3+4+...+2006}=0\)

\(\frac{636363.37-373737.63}{1+2+3+...+2006}=\frac{63.37.10101-63.37.10101}{1+2+3+...+2006}=0\)

63.10101.37-37.10101.63=0

suy ra phep tinh =0

\(\frac{636363.37-373737.63}{1+2+3+...+2006}\)

\(=\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}\)

\(=\frac{0}{1+2+3+...+2006}\)

\(=0\)

\(\frac{636363.37-373737.63}{1+2+3+...+2006}\)

\(\Rightarrow\)\(\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}\)

\(\Rightarrow\frac{63.37-37.63}{1+2+3+...+2006}\)

\(\Rightarrow\frac{2331-2331}{1+2+3+...+2006}\)

\(\Rightarrow\frac{0}{1+2+3+...+2006}\)

\(=0\)

\(P=\dfrac{636363.37-373737.63}{1+2+3+...+2006}\)

Cho \(A=636363.37-373737.63\)

\(A=10101.63.37-10101.37.63\)

\(\Rightarrow A=0\)

Cho \(B=1+2+3+...+2006\)

\(B\) có số số: \(\left(2006-1\right):1+1=2006\) (số)

\(B\) có số cặp: \(2006:2=1003\) (cặp)

\(B=\left(2006+1\right).1003=2013021\)

\(\Rightarrow P=\dfrac{A}{B}=\dfrac{0}{2013021}=0\)

\(A=\frac{636363.37-373737.63}{1+2+3+...+2006}=\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}=\frac{0}{1+2+3+...+2006}=0\)

Tương tự, câu em vừa hỏi, tử số = 0 nên A = 0