a, 10 . 27 - 27 : 9 

= 270 - 3

= 263

b, 7² . 33 + 7² . 67

= 7² ( 33 + 67 )

= 7² . 100

= 49 . 100

= 4900

c, 490 - [ ( 128 + 22 ) : 3 . 2² ] - 7 

= 490 - ( 150 : 3 . 4 ) - 7 

= 490 - ( 50 . 4 ) - 7 

= 490 - 200 - 7

= 290 - 7

= 283

a , ( 456 . 11 - 912 ) . 37 : 13 : 74

= ( 5016 - 912 ) . 37 : 13 : 74

= 4014 . 37 : 13 : 74

= \(\frac{2025}{13}\)

b , [ ( 315 + 372 ) . 3 + ( 372 + 315 ) .7 ] : ( 26 . 13 + 74 . 14 )

= [ 687 . 3 + 687 . 7 ] : ( 338 + 1036 )

= [ 687 . ( 3 + 7 ) ] : 1374

= 6870 : 1374

= 5

\(a.36+15+64\\ =\left(36+64\right)+15\\ =100+15\\ =115\\ b.12\cdot36+12\cdot64\\ =12\cdot\left(36+64\right)\\ =12\cdot100\\ =1200\\ c.\left(3^2+2^3\cdot5\right):7\\ =\left(9+8\cdot5\right):7\\ =\left(9+40\right):7\\ =49:7\\ =7\)\(\)

\(a,36+15+64\)

\(=\left(36+64\right)+15=100+15\)

\(=115\)

\(b,12.36+12.64\)

\(=12.\left(36+64\right)=12.100\)

\(=1200\)

\(c,\left(3^2+2^3.5\right):7\)

=\(\left(9+8.5\right):7\)

\(=49:7=7\)

a)

\(11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)

\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)

\(=\dfrac{146}{13}-\dfrac{18}{7}-\dfrac{68}{13}\)

\(=\left(\dfrac{146}{13}-\dfrac{68}{13}\right)-\dfrac{18}{7}\)

\(=6-\dfrac{18}{7}\)

\(=\dfrac{24}{7}\)

b)

\(\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)

\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)

\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)

\(=\dfrac{2}{7}\times2\)

\(=\dfrac{4}{7}\)

\(a,11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)

\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)

\(=\dfrac{146}{13}-\dfrac{68}{13}-\dfrac{18}{7}\)

\(=6-\dfrac{18}{7}\)

\(=\dfrac{24}{7}\)

\(b,\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)

\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)

\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)

\(=\dfrac{2}{7}\times2\)

\(=\dfrac{4}{7}\)

= -5 / 7 x ( 2 / 11 + 9 / 11) + 12/7

= -5/7 x 1 + 12/7

= -5/7 + 12/7

= 1

b, = ( 9/4 x 105 - 9/4 x 101) : 3/2 - 64 x ( 1/4 - 3/4)

  =  [ 9/4 x ( 105 - 101)] : 3/2 -64 x -1/2

= 9/4 x 4 : 3 /2 - (-32)

= 9 : 3/2 + 32

= 18/3 +32

= 

\(B=7^5:7^3-6^2\cdot2+2^3\cdot2^2\)
\(B=7^2-36\cdot2+2^5\)
\(B=49-36\cdot2+32\)
\(B=49-72+32\)
\(B=9\)

`a,5 xx (-7)+(-2) xx (-5)`

`=5 xx (-7)+5 xx 2`

`= 5 xx (2-7)`

`=5 xx (-5)`

`=-25`

`b,5 xx (-9)+(-2) xx 3`

`=3 xx (-15)+3 xx (-2)`

`=3 xx (-15-2)`

`=3 xx (-17)`

`=-51`

`c,6 xx (-5)^2+3 xx (-15)`

`=2 xx 3 xx 25+3 xx (-15)`

`=3 xx 75-3 xx 15`

`=3 xx (75-15)`

`=3 xx 60`

`=180`

a) 5×(-7) +(-2) ×(-5)

=5.(-7)+2.5

=5.(-7+2)

=5.(-5)=-25

\(3D=\frac{6}{1.7}+\frac{6}{7.13}+....+\frac{6}{601.607}\)

a 150-[ 70 - 3^2]

= 150-[70 -9]

=150-61

=89