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\(a)4567+1234-4567-4\)
\(=4567-4567+1234-4\)
\(=0+1230=1230\)
\(b)2001-53-1519-\left(-53\right)\)
\(=2001-53-1519+53\)
\(=2001-1519-53+53\)
\(=482\)
a. 4567+(1234-4567)-4
=4567+1234-4567-4
=(4567-4567)+(1234-4)
=0+1230
=1230
2001-( 53 -1579 ) - ( - 53 )
=2001-53+1579+53
=(2001+1579)+(53-53)
=3580+0
=3580
35-17 + 2017 - 35 + ( -2017 )
=35-17+2017-35-2017
=(35-35)+(2017-2017)-17
=0+0-17
=-17
a) 4567 + ( 1234 - 4567 ) - 4
= 4567 + 1234 - 4567 - 4
= ( 4567 - 4567 ) + ( 1234 - 4 )
= 0 + 1230
= 1230
b) 2001 - ( 53 - 1579 ) - (-53)
= 2001 - 53 + 1579 + 53
= ( 2001 + 1579 ) - ( 53 - 53 )
= 3580 - 0
= 3580
c) 35 - 17 + 2017 - 35 + (-2017)
= 35 - 17 + 2017 - 35 - 2017
= ( 35 - 35 ) - 17 + ( 2017 - 2017 )
= 0 - 17 + 0
= -17
Bài toán 1 : Tìm x nguyên biết.
a. 3 ≤ x – 2 < 5
=>3-2 < x-2 < 5-2
=>1 < x < 3
=>x=1
Vậy x=1
b. 0 ≤ x – 5 ≤ 2
=>0-5 < x-5 < 2-5
=>-5 < x < -3
=>x=-4
Vậy x=-4
Bài toán 2 : Tính hợp lý.
a. 4567 + (1234 – 4567) -4
=4567+1234-4567-4
=(4567-4567)+(1234-4)
=0+1230
=1230
b. 2001 – (53 + 1579) – (-53)
=2001-53-1579+53
=(2001-1579)+(-53+53)
=422+0
=422
c. 35 – 17 + 2017 – 35 + (-2017)
=(35-35)+[2017+(-2017)]-17-35
=0+0-17-35
=0-17-35
=-52
d. 37 + (-17) – 37 + 77
=(37-37)+[-17+77]
=0+60
=60
e. –(-219) + (-219) – 401 + 12
=0-401+12
=-389
f. |-85| – (-3).15
=85+3.15
=85+45
=130
g. 11.107 + 11.18 – 25.11
=11.(107+18-25)
=11.100
=1100
h. 115 – (-85) + 53 – (-500 + 53)
=115+85+53+500-53
=(53-53)+(115+85+500)
=0+700
=700
k. (-18) + (-31) + 98 + |-18| + (-69)
=-18-31+98+18-69
=(-18+18)+(-31-69)+98
=0+(-100)+98
=-100+98
=-2
Bài toán 4 : Tìm x, biêt.
a. 5x – 16 = 40 + x
5x - x = 40 + 16
4x = 56
x = 56 : 4
x=14
b. 4x – 10 = 15 – x
4x + x = 15 + 10
5x = 25
x = 25 : 5
x = 5
c. -12 + x = 5x – 20
-12 + 20 = 5x - x
8 = 4x
x = 8 : 4
x = 2
d. 7x – 4 = 20 + 3x
7x - 3x = 20 + 4
4x=24
x=24:4
x=6
e. 5x – 7 = – 21 – 2x
5x + 2x = -21+7
7x = -14
x = -14 : 7
x = -2
f. x + 15 = 7 – 6x
x + 6x = 7 - 15
7x = -8
x = -8/7
g. 17 – x = 7 – 6x
17 - 7 = -6x + x
10 = -7x
x=10/-7
h. 3x + (-21) = 12 – 8x
3x + 8x = 12 + 21
11x = 33
x = 33:11
x=3
k. 125 : (3x – 13) = 25
3x-13=125:25
3x-13=5
3x=5+13
3x=18
x=18:3
x=6
l. 541 + (218 – x) = 735
218-x=735-541
218-x=693
x=218-693
x=-475
\(1)5-(1997-2005)+1997\)
\(=5-1997+2005+1997\)
\(=(-1997+1997)+(5+2005)\)
\(=0+2010\)
\(=2010\)
\(2)4567+(1234-4567)-4\)
\(=4567+1234-4567-4\)
\(=(4567-4567)+(1234-4)\)
\(=0+1230\)
\(=1230\)
dễ mà : a, 5 - ( 1997 - 2005 ) +1997
= ( 2005 + 5 ) - ( 1997 - 1997 )
= 2010 - 0
= 2010
a, 5 - (1997 -2005 ) + 1997
= 5 - 1997 + 2005 +1997
= (5 + 2005 ) - ( 1997 - 1997)
= 2010 - 0
= 2010
b, 4567 + (1234 - 4567 )-4
= 4567 + 1234 - 4567 -4
= (4567 - 4567 ) + (1234 - 4)
= 0 + 1230
= 1230
c, 173 - ( 36 + 173 ) + [(175 - 27 ) - 175 - ( -36 + 50 )]
= 173 - 36 - 173 + 175 - 27 - 175 - 36 - 50
= ( 173 - 173 ) + (175 - 175 ) - ( 36 + 36 ) - (27 + 50)
= 72 - 77
= -5
d, 3 . (25 : 5 - 14 : 2 ) - 5 . ( 6 : 2)
= 3 (-2) - 5 .3
= 3 ( -2 - 5 )
= 3 . (-7 )
= - 21
a,3/7 +1/2-[-3]/70
=13/14 -[-3]/70
=65/70 -[-3]/70
=34/35
b,3/5+-1/25 -35/100
=14/25 - 35/100
=56 /100 -35/100
= 21/100
c ,5/12 -3/-16+3/4
=29/48 +3/4
= 29/48 +36/48
=65/48
d, 5/15 +4/-12 +1/7 -1/-6
= 1/3 +1/-3 +1/7-1/-6
=0+1/7-1/-6
= 13/42
A.\(\dfrac{3}{7}+\dfrac{1}{2}+\dfrac{\left(-3\right)}{70}\)
=\([\dfrac{30}{70}+\dfrac{\left(-3\right)}{70}]\)+\(\dfrac{1}{2}\)
= \(\dfrac{27}{70}+\dfrac{35}{70}\)
=\(\dfrac{62}{70}=\dfrac{31}{35}\)
B.\(\dfrac{3}{5}+\dfrac{-1}{25}-\dfrac{35}{100}\)
=\(\dfrac{60}{100}+\dfrac{-4}{100}-\dfrac{35}{100}\)
=\(\dfrac{60+\left(-4\right)-35}{100}\)
=\(\dfrac{21}{100}\)
C.\(\dfrac{5}{12}-\dfrac{3}{-16}+\dfrac{3}{4}\)
=\(\left(\dfrac{5}{12}+\dfrac{9}{12}\right)-\dfrac{-3}{16}\)
=\(\dfrac{7}{6}-\dfrac{-3}{16}\)
=\(\dfrac{56}{48}-\dfrac{-9}{48}\)=\(\dfrac{65}{48}\)
D.\(\dfrac{5}{15}+\dfrac{4}{-12}+\dfrac{1}{7}-\dfrac{1}{-6}\)
=\(\dfrac{1}{3}+\dfrac{1}{7}+(\dfrac{-2}{6}-\dfrac{-1}{6})\)
=\(\dfrac{1}{3}+\dfrac{1}{7}+\dfrac{-1}{6}\)
=\((\dfrac{1}{3}+\dfrac{-1}{6})+\dfrac{1}{7}\)
=\(\dfrac{1}{6}+\dfrac{1}{7}\)=\(\dfrac{13}{42}\)
a, 4567 + ( 1234 - 4567 ) - 4
= 4567 + 1234 - 4567 - 4
=(4567 - 4567) + (1234 - 4)
= 0 + 1230
=1230
b, 2001 - ( 53 + 1579 ) - ( - 53 )
= 2001 - 53 - 1579 + 53
=(2001-1579) - (53 - 53)
= 422 - 0
= 422
c, 79.89 - 79 . ( - 11 ) - 100.79
= 79.(89 + 11 - 100)
= 79.0
= 0
d, 11.107 + 11.18 - 25.11
= 11.(107 + 18 - 25)
= 11. 100
= 1100
e, -69 .|- 45 | -31 . | 45 |
= -69.45 - 31.45
= 45.(-69 - 31)
= 45.(-100)
= -4500
f, 17 . ( 15 - 16 ) + 16
= 17.(15 - 16) + 17 - 1
= 17.(15 - 16 + 1) - 1
= 17.0 - 1
= -1
g, 37.24 + 37.76 + 63.79 + 21.63
= 37.(24 + 76) + 63.(79 + 21)
= 37.100 + 63.100
= 100.(37 + 63)
= 100.100
= 10000
h, 167 + ( - 252 ) + 52 + (- 67 )
= (167 - 67) - (252 - 52)
= 100 - 200
= -100
i, 118 + 107 - (- 118 - 93 ) - 58
= 118 + 107 + 118 + 93 - 58
= (118 + 118 - 58) + (107 + 93)
= 178 + 100
= 278
k, 38 - 138 + 250 - 350
= (38 - 138) + (250 - 350)
= -100 + (-100)
= -200
l, ( 139 - 172 + 99 ) - ( 139 + 199 - 172 )
= 139 - 172 +99 - 139 - 199 + 172
= (139 - 139) - (172 - 172) + (99 - 199)
= 0 - 0 + (-100)
= -100
m, mình không biết nhé :))) thông cảm
sửa lại câu i:
= 118 + 107 + 108 + 93 - 58
= (118 + 118 - 58) + (107 + 93)
= 178 + 200
= 378
Bài 1:
a) - | 12 - 14 | - | 98 - 15 + 2 | - 14
= - | - 2 | - | 85 | - 14
= -2 - 85 - 14
= -101
b) ( -24 ) - ( 12 - 19 ) - | 15 - 12 - 7 |
= ( -24 ) - ( - 7 ) - | -4 |
= ( -24 ) + 7 - 4
= -21
Bài 2:
a) 5 - ( 1997 - 2005 ) + 1997
= 5 - 1997 + 2005 + 1997
= ( 5 + 2005 ) + ( 1997 - 1997 )
= 2010 + 0
= 2010
b) 1579 - ( 53 + 1679 ) - ( -53 )
= 1579 - 53 - 1679 + 53
= ( 1579 - 1679 ) + ( 53 - 53 )
= ( -100 ) + 0
= -100
c) -48725 - ( 357 - 48725 ) + 300
= -48725 - 357 + 48725 + 300
= [( -48725 ) + 48725 ] + ( 357 - 300 )
= 0 + ( -57 )
= -57
d) 4567 + ( 1234 - 4567 ) - 4
= 4567 + 1234 - 4567 - 4
= ( 4567 - 4567 ) + ( 1234 - 4 )
= 0 + 1230
= 1230
a) \(-\left|12-14\right|-\left|98-15+2\right|-14\)
\(=-\left|2\right|-\left|85\right|-14\)
\(=\left(-2\right)-85-14\)
\(=\left(-2\right)-\left(85+14\right)\)
\(=\left(-2\right)-99\)
\(=\left(-2\right)+\left(-99\right)=-101\)