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\(25\cdot69+31\cdot25-150\)
\(=25\cdot\left(69+31\right)-150\)
\(=25\cdot100-150\)
\(=2500-150\)
\(=2350\)

= 25 . ( 69 + 31 ) -150

= 25 . 100 - 150

= 2500 - 150 = 2350

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\(=\dfrac{-23-28}{24}=\dfrac{-51}{24}=\dfrac{-17}{8}\)

\(\dfrac{-17}{8}\)

\(a,=\dfrac{21}{48}+\dfrac{10}{48}=\dfrac{31}{48}\\ b,=\dfrac{44}{60}-\dfrac{25}{60}=\dfrac{19}{60}\)

\(a,27.5^2-25.127=27.25-25.127=25\left(27-127\right)=25.\left(-100\right)=-2500\\ b,\dfrac{-5}{12}+\dfrac{3}{4}+\dfrac{1}{-3}=\dfrac{-5}{12}+\dfrac{9}{12}-\dfrac{4}{12}=\dfrac{0}{12}=0\)

a = -2500

b = 0

a)3⁶:3²+2³.2²-3³.3 

= 3⁴+2⁵-3⁴

=2⁵

=32

b)3⁸:3⁴-9⁵:9³

= 3⁴-9²

= 3⁴-3⁴

= 0

c)2³.15+2³.35

= 2³(15+35)

= 8.50

= 400

a: \(3^6:3^2+2^3\cdot2^2-3^3\cdot3\)

\(=3^4+32-3^4\)

=32

b: \(3^8:3^4-9^5:9^3\)

\(=3^4-9^2\)

=0

c: Ta có: \(2^3\cdot15+2^3\cdot35\)

\(=8\cdot50\)

=400

A) 4¹⁰ . 8¹⁵ = (2²)¹⁰ . (2³)¹⁵ = 2²⁰ . 2⁴⁵ = 2²⁰⁺⁴⁵=2⁶⁵

B) 4¹⁵ . 5³⁰ = (2²)¹⁵ . 5³⁰ = 2³⁰ . 5³⁰ = (2 . 5)³⁰ = 10³⁰

C) 27¹⁶ : 9¹⁰ = (3³)¹⁶ : (3²)¹⁰ = 3⁴⁸ : 3²⁰ =  3^48-20=3²⁸

20²-15².3[5²+22+2022⁰

A) 220+[4+ (-220)+(-36) = -32

b)(-9)-[(-6)+8] = -11

c)22.154+22.(-54) = 2200

a)-32

b)-11

c)2200