\(x.y+x+y=36\)

\(x\left(y+1\right)+y=36\)

\(x\left(y+1\right)+\left(y+1\right)=36+1\)

\(\left(y+1\right)\left(x+1\right)=37\)

\(\left(y+1\right)\left(x+1\right)\) có  4 cặp: \(y+1=1;x+1=37\) 

                                         \(y+1=37;x+1=1\)

                                         \(y+1=-1;x+1=-37\)

                                         \(y+1=-37;x+1=-1\)

\(x;y\) có 4 cặp: \(y=0;x=36\)

                      \(y=36;x=0\)

                      \(y=-2;x=-38\)

                      \(y=-38;x=-2\)

Ta có   8 5 = − 12 x  => 8. x = -12 . 5=> x = - 15 2  ( KTM)

=>10x=-100

hay x=-10

⇒3x+7x=-64-36

⇒10x=-100

⇒x=-10

12 x = 30 − 6 12 x = 24       x = 24 : 12       x = 2

12 x = 30 − 6 12 x = 24       x = 24 : 12       x = 2

      3/x = y/35= -36/84

⇒  y = \(\dfrac{35.-36}{84}\) = - 15 

⇒  x = \(\dfrac{3.35}{-15}\) = - 7 

     Vậy x = - 7 và y = -15 

thanks bn

\(3x+36=-7x-64\)

\(10x=-100\)

\(x=-10\)

\(-5x-178=14x+145\)

\(-19x=323\)

\(x=-17\)