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A= (910.510.510)/(2510.310)=(320.520)/(520.310)=310
B=(0,8)5/(0,4)6= (2.0,4)5/0,4.0,45 = 25.0,45/0,4.0,45 = 25/0,4 = 80
C= 215.94/66.83= 215.38/36.26.29=215.38/36.215=32=9
tìm giá trị của biểu thức sau
a) 45 mũ 10 . 5 mũ 20 / 75 mũ 15
b) (0,8) mũ 5 / (0,4) mũ 6
c) 2 mũ 15 . 9 mũ 4 / 6 mũ 6 . 8 mũ 3
bài làm là:
a) 45^10.5^20/75 ^ 15
=(5.9)^10.5^20/(5.15)^15
=5^10.9^10.5^20/5^15.15^15
=5^30.3^20/5^15.3^15.5^15
=5^30.3^20/5^30.3^15
=5^30.3^20/5^30.3^15
=3^5
=243
mấy ý kia mình chia tính được ....A,hihi
(4510 x 520 ) / 7515=243
(0.8)5 / (0.4)6=0
215 x 94 / 66 x 83=9
\(\frac{45^{10}.5^{20}}{75^{15}}=\frac{\left(3^2.5\right)^{10}.5^{20}}{\left(3.5^2\right)^{15}}=\frac{3^{20}.5^{10}.5^{20}}{3^{15}.5^{30}}=\frac{3^{20}.5^{30}}{3^{15}.5^{30}}=3^5=243\)
\(\frac{\left(0,8\right)^5}{\left(0,4\right)^6}=\frac{\left(0,4.2\right)^5}{\left(0,4\right)^6}=\frac{\left(0,4\right)^5.2^5}{\left(0,4\right)^6}=\frac{2^5}{0,4}=\frac{32}{\frac{2}{5}}=32.\frac{5}{2}=80\)
\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^6.3^6.2^9}=\frac{2^{15}.3^8}{2^{15}.3^6}=3^2=9\)
Bài làm
\(A=\frac{45^{10}\cdot5^{20}}{75^{15}}\)
\(A=\frac{\left(3^2\right)^{10}\cdot5^{10}\cdot5^{20}}{3^{15}\cdot\left(5^2\right)^{15}}\)
\(A=\frac{3^{20}\cdot5^{30}}{3^{15}\cdot5^{30}}\)
\(A=3^5\)
Vậy \(A=3^5\)
\(B=\frac{2^{15}\cdot5^{20}}{6^6\cdot8^3}\)
\(B=\frac{2^{15}\cdot5^{20}}{2^6\cdot3^3\cdot\left(2^3\right)^3}\)
\(B=\frac{2^{15}\cdot5^{20}}{2^{15}\cdot3^3}\)
\(B=\frac{5^{20}}{3^3}\)
Vậy \(B=\frac{5^{20}}{3^3}\)
=\(\left[\dfrac{\left(0,4.2\right)^5}{\left(0,4\right)^6}+\dfrac{2^9.2^6.3^8}{\left(3.2\right)^6.2^9}\right]=\left[\dfrac{\left(0,4\right)^5.2^5}{\left(0,4\right)^6}+\dfrac{2^6.3^8}{3^6.2^6}\right]\)
=\(\left[\dfrac{2^5}{0,4}+3^2\right]\)
=\(\left[80+9\right]=89\)
\(\left[\dfrac{\left(2.0,4\right)^5}{0,4,0,4^5}+\dfrac{2^{15}.3^8}{3^6.2^6.2^9}\right]\div\dfrac{3^{20}.5^{30}}{3^{15}.5^{30}}\)
\(=\left[\dfrac{2^5.0.4^5}{0,4.0,4^5}+\dfrac{2^{15}.3^8}{3^6.2^{15}}\right]\div3^5\)
\(=\left[\dfrac{2^5}{0,4}+3^2\right]\div243\)
\(=80+\left(3^5\div3^2\right)\)
\(=80+3^3\)
\(=80+27\)
\(=107\)