1-2x =8

=> 2x = 1-8

=> 2x = -7

=>x =-7 : 2

=> x =  -3,5

Vậy tac có:

2x-1+ /-3,5/

= 2x-1+ 3,5 = 2x- 4,5

ko hiểu đè bài lám nên làm sai bỏ qua nhá :>>>

Ta có: |2x-1|+|1-2x|=8

\(\Leftrightarrow\left|2x-1\right|+\left|2x-1\right|=8\)(Vì 2x-1 và 1-2x là hai số đối nhau)

\(\Leftrightarrow2\left|2x-1\right|=8\)

\(\Leftrightarrow\left|2x-1\right|=4\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-1=4\\2x-1=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=5\\2x=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)

Vậy: \(x\in\left\{\dfrac{5}{2};-\dfrac{3}{2}\right\}\)

Ta có:3x-/2x-2/=1

=>/2x-2/=3x-1

Vì /2x-2/\(\ge\)0=>3x-1\(\ge\)0=>3x\(\ge\)1=>x\(\ge\)1

Vì x\(\ge\)1=>2x-2\(\ge\)0 =>/2x-2/=2x-2

Hay 2x-2=3x-1

2x-3x=-1+2

-x=1

x=-1

\(2x\left|x-1\right|+5x\left|x-1\right|-8x\left|x-1\right|=7\)

\(\left|x-1\right|.\left(2x+5x-8x\right)=7\)

\(\left|x-1\right|.\left(-x\right)=7\)

\(\left|x-1\right|=\frac{-7}{x}\) ( với \(x\ne0\))

!2x-1!=!1-2x!

=>2. !2x-1!=8

2x-1=4=> x=5/2

2x-1=-4=> x=-3/2

!2x-1!=!1-2x!

=> 2.!2x-1!=8

2x-1=4=>x=5/2

2x-1=-4=>x=-3/2

Mk đg cần gấp. TKS mn

mn giúp mik với

ai nhanh nhất mik cho 5 sao