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\(\dfrac{2x-9}{240}\) \(=\) \(\dfrac{39}{80}\) \(\Leftrightarrow\) \(\left(2x-9\right)\) \(.80\) \(=\) \(240.39\)
\(2x\) \(-\) \(9\) \(=\) ( \(240\) \(.\) \(39\) ) \(:\) \(80\)
\(2x\) \(-\) \(9\) \(=\) \(117\)
\(2x\) \(=\) \(126\)
\(x\) \(=\) \(63\)
\(\frac{2x-9}{240}=\frac{39}{80}\Leftrightarrow\left(2x-9\right).80=240.39\)
\(2x-9=\left(240.39\right):80\)
\(2x-9=117\)
\(2x=126\)
\(x=63\)
2x-9 / 240 = 39 / 80
2x-9 / 240 = 117 / 240
2x - 9 = 117
2x = 117 + 9
2x = 126
x = 126 : 2
x = 63
Vậy x = 63
\(\frac{2x-9}{240}=\frac{39}{80}\)
\(\Rightarrow\frac{2x-9}{240}=\frac{117}{240}\)
\(\Rightarrow2x-9=117\)
\(\Rightarrow2x=117+9\)
\(\Rightarrow2x=126\)
\(\Rightarrow x=126:2\)
\(\Rightarrow x=63\)
Vậy \(x=63\)
Chúc bạn học tốt !!!
Ta có:\(\frac{2x-9}{240}=\frac{39}{40}\Rightarrow\frac{2x-9}{240}=\frac{234}{240}\)
=>2x-9=234
=>2x=234+9
=>2x=243
=>x=243:2
=>x=121,5
Mà x là số nguyên nên không có x thỏa mãn
Ta có: \(\frac{2x-9}{240}=\frac{39}{80}=\frac{117}{240}\)
=>\(2x-9=117\)
\(2x=117+9=126\)
\(x=126:2=63\)
\(\dfrac{2x-9}{240}=\dfrac{117}{240}\)
=> 2x -9=117
2x=117+9
2x=126
x=126/2
x=63
\(\dfrac{2x-9}{240}\)=\(\dfrac{117}{240}\)
►2x-9=117
2x=117+9
2x=126
x=126:2
x=63
Vậy:x=63
\(\dfrac{2x-9}{240}\)=\(\dfrac{39}{80}\)\(\Rightarrow\)\(2x-9\)=\(\dfrac{240.39}{80}\)=\(117\)
\(2x-9=117\)\(\Rightarrow\)\(2x=117+9=126\)\(\Rightarrow\)\(x=126:2=63\)
\(\dfrac{2x-9}{240}\)=\(\dfrac{39}{80}\) \(\Rightarrow\) \(2x-9=\)\(\dfrac{240.39}{80}\)=117
\(2x-9=117\)\(\Rightarrow\)\(2x=117-9=108\)\(\Rightarrow\)\(x=108:2=54\)
2x−92402x−9240=39803980⇒⇒2x−92x−9=240.3980240.3980=117117
2x−9=1172x−9=117⇒⇒2x=117+9=1262x=117+9=126⇒⇒x=126:2=63
\(\dfrac{2x-9}{240}=\dfrac{39.3}{240}\Leftrightarrow2x-9=117\Leftrightarrow x=\dfrac{117+9}{2}=\dfrac{126}{2}=63\)