a,   -14 - 7 + x = -12

    \(\Leftrightarrow-21+x=-12\)

    \(\Leftrightarrow x=-12+21\)

    \(\Leftrightarrow x=9\)

b,    \(x+\left(-15\right)-\left(-6\right)=11\)

\(\Leftrightarrow x-15+6=11\)

\(\Leftrightarrow x-\left(15-6\right)=11\)

\(\Leftrightarrow x-9=11\)

\(\Leftrightarrow x=11+9\)

\(\Leftrightarrow x=20\)

 c,   \(x-\left[18+\left(-7\right)\right]=15\)

\(\Leftrightarrow x-\left(18-7\right)=15\)

\(\Leftrightarrow x-11=15\)

\(\Leftrightarrow x=15+11\)

\(\Leftrightarrow x=26\)     

d,   \(-84-\left(-18-6\right)=x+\left(-20\right)\)

\(\Leftrightarrow-84-\left(-24\right)=x+\left(-20\right)\)

\(\Leftrightarrow-84+24=x+\left(-20\right)\)

\(\Leftrightarrow-60=x+\left(-20\right)\)

\(\Leftrightarrow x=-20+60\) 

\(\Leftrightarrow x=40\)

c)x-11=15

x=26

Bài 13: 

a: =>20-x=15-8+13=20

hay x=0

`a)`

`x-15 = -21`

`<=> x = -21 + 15`

`<=> x = -6`

`b)`

`42 - x = -7`

`<=> x = 42 - (-7)`

`<=> x = 42 + 7`

`<=> x = 49`

`c)`

`12 - (30-x) = -23`

`30-x = 12 - (-23)`

`30-x = 35`

`x = 30-35`

`x = -5`

`d)`

`31 - (17+x)=18`

`<=> 17+x = 31-18`

`<=> 17+x =13`

`<=> x = 13-17`

`<=> x = -4`

Sai thông cảm nha :)

a) \(x-15=-21\)

\(\Rightarrow x=-21+15=-6\)

b) \(42-x=-7\)

\(\Rightarrow x=42+7=49\)

c) \(12-\left(30-x\right)=-23\)

\(\Rightarrow30-x=12+23=35\)

\(\Rightarrow x=30+35=65\)

d) \(31-\left(17+x\right)=18\)

\(\Rightarrow17+x=31-18=13\)

\(\Rightarrow x=13-17=-4\)

a) $x-15=-21$

$\Rightarrow x=-21+15=-6$

b) $42-x=-7$

$x=42+7=49$

c) $12-\left(30-x\right)=-23$

$30-x=12+23=35$

$x=30+35=65$

d) $31-\left(17+x\right)=18$

$17+x=31-18=13$

$x=13-17=-4$

lười lắm ko rảnh mà giải hộ đâu mai thi rồi

ko rảnh thì thôi đừng trả lời linh tinh chứ

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a) Ta có: 12-5x=37

\(\Leftrightarrow5x=-25\)

hay x=-5

Vậy: x=-5

b) Ta có: 7-3|x-2|=-11

\(\Leftrightarrow3\left|x-2\right|=18\)

\(\Leftrightarrow\left|x-2\right|=6\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=6\\x-2=-6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-4\end{matrix}\right.\)

Vậy: \(x\in\left\{8;-4\right\}\)

c) Ta có: \(x+\dfrac{2}{8}=-\dfrac{15}{4}\)

\(\Leftrightarrow x=\dfrac{-15}{4}-\dfrac{2}{8}=\dfrac{-15}{4}-\dfrac{1}{4}\)

hay x=-4

Vậy: x=-4

a, \(\Leftrightarrow5x=12-37=-25\)

\(\Leftrightarrow x=-\dfrac{25}{5}=-5\)

Vậy ...

b, \(\Leftrightarrow3\left|x-2\right|=7+11=18\)

\(\Leftrightarrow\left|x-2\right|=\dfrac{18}{3}=6\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=6\\x-2=-6\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-4\end{matrix}\right.\)

Vậy ...

c, \(\Leftrightarrow x=-\dfrac{15}{4}-\dfrac{2}{8}=-4\)

Vậy ..

Tao học lớp 5 làm sao mà giải được hả?

a, x - 96 = ( 443 - x ) - 15

    x - 96 = 443 - x - 15

    x - 96 = 428 - x 

     x + x = 428 + 96

         2x = 524

           x = 262

b, ( x - 12 ) - 15 = ( 20 - 7 ) - ( 18 - x )

        x - 12 - 15 = 13 - 18 + x 

               x - 27 = - 5 + x

                 x - x = - 5 + 27 

                    0x = 22

=> ko có giá trị nào thõa mãn 

c, 353 - x = 46 + ( 3x - 21 )

    353 - x = 46 + 3x - 21

    353 - x = 25 + 3x 

    - x - 3x = 25 - 353

         - 4x = - 328

             x = 82

d, - ( x + 81 ) = ( 2x +12 ) - ( 5 + x )

         - x - 81 = 2x + 12 - 5 - x

         - x - 81 = x + 7 

           - x - x = 7 + 81

              - 2x = 88

                  x = - 44 

e, ( - x + 821 + 534 ) = 499 + ( x - 84 )

               - x + 1355 = 499 + x - 84

                      - x - x = 499 - 84 - 1355

                         - 2x = - 940

                             x = 470

g, x + 53 = ( 400 - 9x ) - 447

    x + 53 = 400 - 9x - 447

    x + 53 = - 47 - 9x

    x + 9x = - 47 - 53

        10x = -100

           x = - 10