9^x+2+9^x-9².82 =0

<=> 9^x(9²+1)=9².82 

<=> 9^x.82 = 9².82

<=> 9^x = 9²

<=> x = 2

mk ghi lại đề nha:

27ⁿ : 9ⁿ = 9²⁷ : 81

(27 : 9)ⁿ = 9²⁷ : 9²

\(\Rightarrow\)     3ⁿ  = 9²⁵

\(\Rightarrow\)      3ⁿ = (3²)²⁵

\(\Rightarrow\)      3ⁿ  = 3⁵⁰

Vậy n = 50

\(27^n.9^n=9^{27}:81\Rightarrow3^{3n}:3^{2n}=3^{54}:3^4=3^{50}\)

\(\Rightarrow3^{5n}=3^{50}\Rightarrow5n=50\Rightarrow n=\frac{50}{5}=10\)

9ⁿ : 3ⁿ = 3

<=> (3²)ⁿ : 3ⁿ = 3¹

<=> 3²ⁿ : 3ⁿ = 3¹

<=> 3^{2n - n} = 3¹

<=> 3ⁿ = 3¹

<=> n = 1

cảm ơn pro

\(27^n.9^n=9^{27}:81\)

\(3^{3n}.3^{2n}=3^{54}:3^4\)

\(3^{5n}=3^{50}\)

=> 5n = 50

=> n = 10

c: \(\Leftrightarrow x\cdot\left(\dfrac{5}{7}\right)^{11}=\left(\dfrac{5}{7}\right)^{12}\cdot7\)

\(\Leftrightarrow x=\left(\dfrac{5}{7}\right)^{12}:\left(\dfrac{5}{7}\right)^{11}\cdot7=\dfrac{5}{7}\cdot7=5\)

d: \(\Leftrightarrow9^x\cdot81+9^x-9^2\cdot82=0\)

\(\Leftrightarrow9^x\cdot82=9^2\cdot82\)

\(\Leftrightarrow9^x=9^2\)

hay x=2

c: 

d: 

vậy x=2

m

2024 thì bn này ngoài 20 tuổi r trả lời gì nữa :>

2^n/32 = 4 => 2^n = 4 . 32 = 128 => n =7

27^n . 9^n = 9^27 . 81 

=> (27.9)^n = 9^27 . 9^2

=> 243^n = 9^54

=> 243^n = 243^1458

vay n=1458

1/9 . 3^4 . 3^n+1 = 9^4

=> 9 . 3^n+1 = 6561

=> 3^n+1 = 6561 /9

=> 3^n+1 = 729

=> n = 5