a: Ta có: \(100-7\left(x-5\right)=58\)

\(\Leftrightarrow7\left(x-5\right)=42\)

\(\Leftrightarrow x-5=6\)

hay x=11

b: Ta có: \(12\left(x-1\right):3=4^3+2^3\)

\(\Leftrightarrow12\left(x-1\right)=216\)

\(\Leftrightarrow x-1=18\)

hay x=19

Hoctot

\(7^5:7^3-x=23\)

\(7^2-x=23\)

\(49-x=23\)

\(x=49-23\)

\(x=26\)

\(\left(2x-7\right).5^8=5^{10}\)

\(\left(2x-7\right)=5^{10}:5^8\)

\(2x-7=5^{10-8}\)

\(2x-7=5^2\)

\(2x-7=25\)

\(2x=32\)

\(x=32:2\)

\(x=16\)

* Mình nghĩ câu a sửa đề như vậy sẽ đúng hơn!

123 - 5(x + 4) = 38

=> 5(x + 4) = 85

=> x + 4 = 17

=> x = 13

vậy_

(3x - 24).73 = 2.7

=> (3x - 24).73 = 14

=> 3x - 24 = 1022

=> 3x = 1046

=> x = 1046/3

(3x − 24).73 = 2.74

3x − 24 = 2.74 : 73

3x − 24 = 2.74 - 1

3x – 16 = 2.7

3x – 16 = 14

3x = 14 + 16

3x = 30

x = 30 : 3

x = 10

Vậy x = 10

B

B

\(Ư\left(30\right)=\left\{1;2;3;5;6;10;15;30\right\}\\ \Rightarrow x=5\left(B\right)\\ B\left(8\right)=\left\{0;8;16;24;32;...\right\}\\ \Rightarrow x=24\left(B\right)\)

a. 5x(x-100)=0

=> TH1 : 5x=0 => x= 0

TH2 : x-100 = 0 => x= 100

Vậy .......

b. 34x (2x-6) =0

TH1: 34x=0 => x= 0

TH2; 2x-6=0 => 2x= 6 => x = 3

Vậy ............

a,5x(x-100)=0

=> 5x=0 hoac x-100=0

=> x=0 hoac x=100

b,34x(2x-6)=0

=> 34x=0 hoac 2x-6=0

=>x=0 hoac x=3

c,3x(x+7)-15=27

phan nay nhieu truong hop lam ban dong nao nha goi y

3x=6hoac21

x+7=7hoac 2

va co 4truong hop

phan con lai ko ro ban viet lai di

\(\left(5x-24\right).73=2.74\)

\(\Leftrightarrow\left(5x-24\right).73=148\)

\(\Leftrightarrow5x-24=\frac{148}{73}\)

\(\Leftrightarrow5x=\frac{148}{73}+24\)

\(\Leftrightarrow5x=\frac{1900}{73}\)

\(\Leftrightarrow x=\frac{1900}{73}.\frac{1}{5}\)

\(\Leftrightarrow x=\frac{380}{73}\)

bạn k làm ra phân số được không

5x - 24 = 66 

5x = 66 + 24

5x = 90 

x = 90 : 5 

x = 18 

Vậy x = 18 

`5x - 24 = 66`

`5x = 66 + 24`

`5x = 90`

`x = 90 : 5`

`x = 18`

Vậy `x = 18`

`@btran`