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\(5^{x-1}+5^{x-2}+5^{x-3}=775\\ 5^{x-3}.\left(25+5+1\right)=775\\ 5^{x-3}.31=775\\ 5^{x-3}=\dfrac{775}{31}=25=5^2\\ x-3=2\\ x=5\)
\(5^x+5^{x+1}+5^{x+2}=775\)
\(\Leftrightarrow5^x.1+5^x.5+5^x.5^2=775\)
\(\Leftrightarrow5^x.\left(1+5+5^2\right)=775\)
\(\Leftrightarrow5^x.\left(1+5+25\right)=775\)
\(\Leftrightarrow5^x.31=775\)
\(\Rightarrow5^x=775:31=25=5^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
\(5^x+5^{x+1}+5^{x+2}=775\)
<=>\(5^x.\left(1+5+5^2\right)=775\)
<=>\(5^x.31=775\)
<=>\(5^x=775:31\)
<=>\(5^x=25\)=>\(x=2\)
a, \(-5x-1-\dfrac{x}{2}+\dfrac{1}{3}=\dfrac{3}{2}x-5\Leftrightarrow-7x=-\dfrac{13}{3}\Leftrightarrow x=\dfrac{13}{21}\)
b, \(3x-\dfrac{3}{2}-5x-3=-x+\dfrac{1}{5}\Leftrightarrow-x=\dfrac{47}{10}\Leftrightarrow x=-\dfrac{47}{10}\)
a) \(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0\)
\(\Rightarrow3x-1=0\Rightarrow3x=1\Rightarrow x=\frac{1}{3}\)
\(\frac{-1}{2}x+5=0\Rightarrow\frac{-1}{2}x=-5\Rightarrow x=10\)
b) \(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=x+\frac{1}{5}\)
\(3x-\frac{3}{2}-5x-3=x+\frac{1}{5}\)
\(\Rightarrow3x-5x-x=\frac{1}{5}+\frac{3}{2}+3\)
\(-3x=\frac{47}{10}\)
\(x=\frac{-47}{30}\)
c) \(-5.\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(-5x-1-\frac{1}{2}x+\frac{1}{3}=\frac{3}{2}x-\frac{5}{6}\)
\(-5x-\frac{1}{2}x-\frac{3}{2}x=\frac{-5}{6}+1-\frac{1}{3}\)
\(-7x=\frac{-1}{6}\)
\(x=\frac{1}{42}\)
d) \(3.\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(3.\left(3x-\frac{1}{2}\right)^3=\frac{-1}{9}\)
\(\left(3x-\frac{1}{2}\right)^3=\frac{-1}{27}\)
\(\left(3x-\frac{1}{2}\right)^3=\left(\frac{-1}{3}\right)^3\)
\(\Rightarrow3x-\frac{1}{2}=\frac{-1}{3}\)
\(3x=\frac{1}{6}\)
\(x=\frac{1}{18}\)
Học tốt nhé bn!
5x + 5x + 1 + 5x + 2 = 775
\(\Rightarrow\) 5x + 5x + 1 + 5x + 2 = 52 + 52 + 1 + 52 + 2
\(\Rightarrow\) x = 2
5x + 5x+1 + 5x+2 = 775
5x . 1 + 5x . 5 + 5x + 52 = 775
5x . (1 + 5 + 25 ) = 775
5x . 31 = 775
5x = 775 : 31
5x = 25
5x = 52
x=2