9-25=(7-x)-(25+7)

9-25=(7-x)-32

suy ra:(7-x)-32=9-25

(7-x)-32=-16

7-x=-16+32

7-x=16

x=7-16

x=-9

9-25=(7-x)-(25+7)

( 7 - x ) - ( 25 + 7 ) = 9 - 25

( 7 - x ) - 32 = - 16

     7 - x      = ( - 16 ) + 32 

      7 - x     = 16

           x     = 7 - 16

           x     = - 9

Vậy x = - 9 

9 - 25 = ( 7 - x ) - ( 25 + 7 )

x = 7 - 25 - 7 - 9 + 25

x = ( 7 - 7 ) + ( 25 - 25 ) -9

x =  0  + 0 - 9

x= - 9

=> x= - 9 

Vậy x = - 9

\(\left(x-7\right)\left(x+2019\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-7=0\\x+2019=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=7\\x=-2019\end{cases}}\)

\(9-25=\left(7-x\right)-\left(25+7\right)\)

\(\Leftrightarrow-16=7-x-25-7\)

\(\Leftrightarrow-x=-16+25\)

\(\Leftrightarrow-x=9\)

\(\Leftrightarrow x=-9\)

\(2\left(4x-2x\right)-7x=15\)

\(\Leftrightarrow4x-7x=15\)

\(\Leftrightarrow x=-5\)

a ) 9 - 25 = ( 7 - x ) - ( 25 + 7 )

    9 - 25  =  7 - x - 25 - 7 

  9 - 25 - 7 + 25 + 7 = -x 

9        = - x

 => x = -9

Vậy x = -9

b) 2 . ( 4x - 2x ) - 7x = 15

    8x  - 4x - 7x          = 15 

-3x = 15

  x   =  15 : ( - 3 ) 

  x = -5 

Vậy x = -5

c ) ( x - 7 ). ( x + 2019 ) = 0

 => x - 7 = 0 hoặc x + 2019 = 0

   => x    = 7 hoặc x = - 2019 

 vậy x \(\in\){ 7 ; -2019 }

Ta có 2(x+3)=3(1-x)-2

suy ra : 2x + 6 = 3 -3x -2

            2x +6 = 1-3x

            2x +6 -1 +3x=0

            5x+5 =0

           5(x+1)=0

    Vậy x bằng -1

bí rùi, nếu chỉ có 1 cái x thì mình giải được

a) |x + 4| = 17

=> \(\orbr{\begin{cases}x+4=17\\x+4=-17\end{cases}}\)

=> \(\orbr{\begin{cases}x=13\\x=-21\end{cases}}\)

b) (7 - x) - (25 + 7) = -25

=> (7 - x) - 32 = -25

=> 7 - x = -25 + 32

=> 7 - x = 7

=> x = 7 - 7

=> x = 0

c. |x + 5| = |-7|

=> |x + 5 | = 7

=> \(\orbr{\begin{cases}x+5=7\\x+5=-7\end{cases}}\)

=> \(\orbr{\begin{cases}x=2\\x=-12\end{cases}}\)

2) 4 . (-5)² + 2 . (-15)

= 2. 2 . 25 + 2 . (-15)

= 2.(2 . 25 - 15)

= 2 . 35

= 70

a)|x-3|=7-(-2)

|x-3|=9

x-3=9

th1:x-3=9       th2:x-3=-9

x=9+3=12       x=(-9)+3=-6

b. ( 7-x ) - ( 25+7) = -25        c. (3x - 2 mũ 4 ) . 7 mũ 3 = 2. 7 mũ 4             

7-x-25-7=-25                            3x-2^4=2.7^4:7^3

-x-25=-25                                  3x-16=14

-x=0                                           3x=30

vậy x=0                                      vậy x=10

9-25=(7-x)-(25+7)

-16=7-x-32

7-x-32=16

7-x=-16+32

7-x=16 

x=16+7

x=23

B,35-3.|x|=5.(2^3-4)

35-3.x=5.(8-4)

35-3.x=5.4

35-3.x=20

3.x=35-20

3.x=15

X=15:3

x =5

C, -6x=18

-6.x=18

X=18:(-6)

X= -3

D,10+2.|x|=2.(3^2-1)

10+2.x=2.8

10+2.x=16

2.x=16-10

2.x =6

X=6:2

x=3

Ok k mk nha 

a) 9 - 25 = ( 7 - x) - (25+7)

    - 16 =  7-x - 32

    7 - x - 32 = -16

   7 - x = -16 + 32

   7 - x = 16

      x = 16 + 7

      x = 23

b) -6x = 18

   - 6 .x = 18

        x = 18 : (-6)

       x = -3

a) |x+2| = 0

⇒ x+2 = 0

x = 0 - 2

x =-2

Vậy : x =-2

\(b,\left|x-5\right|=\left|-7\right|\\ \left|x-5\right|=7\\ \Rightarrow\left[{}\begin{matrix}x-5=7\\x-5=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-2\end{matrix}\right.\\ Vậy...\\ c,\left|x-3\right|=\left|5\right|+\left|-7\right|\\ \left|x-3\right|=5+7\\ \left|x-3\right|=12\\ \Rightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\\Vậy...\\ d,\left(7-x\right)-\left(25+7\right)=-25\\ 7-x-32=-25\\ 7-x=-25+32\\ 7-x=7\\ x=7-7\\ x=0\\ Vậy...\\ e,\left|x-3\right|=7-\left(-2\right)\\ \left|x-3\right|=9\\ \Rightarrow\left[{}\begin{matrix}x-3=9\\x-3=-9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-6\end{matrix}\right.\\ Vậy...\)