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= 2.(1+2+3+4+.....+x)=210
=1+2+3+4+........+x=210:2
=1+2+3+4+....+x=105
=(x+1).x:2=105
=(x+1).x=105.2
=(x+1).x=210
=(x+1).x=14.15
Vay x=14
2+4+6+8+...+2x=210
=>2.1+2.2+2.3+2.4+...+2.x=210
=>2.(1+2+3+4+...+x)=210
=>1+2+3+4+...+x=210:2
=>1+2+3+4+...+x=105
=>x=14
2+4+6+8+...+2x=210
=>2.1+2.2+2.3+2.4+...+2.x=210
=>2.(1+2+3+4+...+x)=210
=>1+2+3+4+...+x=210:2
=>1+2+3+4+...+x=105
=>x=14
2*(1+2+3+..+x)=210
2*(x+1)*x/2=210
(x+1)x=210
x=14
2+4+6+...+2x=210
=2(1+2+3+...+x)=210
=1+2+3+...+x=105
=x+1.x/2=105
(x+1)x=210
14.15=210
=>x=14
Vậy x=14
2 + 4 + 6 + 8 + ... + 2.x = 210
=> 2.1 + 2.2 + 2.3 +2.4 + ... + 2.x = 210
=> 2.( 1 + 2 + 3 + 4 + ... +x ) = 210
=> 2. [ x.( x+ 1) /2 ] = 210
=> x. ( x + 1 ) = 210
hay x.( x + 1) = 14.(14 + 1)
Vậy x = 14
\(2+4+6+8+...+2.x=210\)
\(=2.1+2.2+2.3+...+2.x=210\)
\(=2.\left(1+2+3+....+x\right)=210\)
=\(2.\left[\frac{x.\left(x+1\right)}{2}\right]=210\)
\(\Rightarrow x.\left(x+1\right)=14.\left(14+1\right)\)
\(=x.\left(x+1\right)=210\)
=> x=14
2 + 4 + 6 + 8 + ... + 2.x = 210
=> 2.1 + 2.2 + 2.3 +2.4 + ... + 2.x = 210
=> 2.( 1 + 2 + 3 + 4 + ... +x ) = 210
=> 2. [ x.( x+ 1) /2 ] = 210
=> x. ( x + 1 ) = 210
hay x.( x + 1) = 14.(14 + 1)
Vậy x = 14
2+4+6+8+...+2x=210
+) Ta có : 2.1+2.2+2.3+2.4+...+2x=210
=>2.(1+2+3+...x) =210
1+2+3+...+x= 210:2
1+2+3+...+x= 105
(x+1).x:2=105 =>(x+1).x=210 =>15.14=210 +) Vậy x=14