\(2009-\left(4\frac{5}{9}+x-7\frac{7}{18}\right):15\frac{2}{3}=2008\)

\(2009-\left(\frac{41}{9}+x-\frac{133}{18}\right):\frac{47}{3}=2008\)

\(\left(\frac{41}{9}+x-\frac{133}{18}\right):\frac{47}{3}=2009-2008\)

\(\left(\frac{41}{9}+x-\frac{133}{18}\right):\frac{47}{3}=1\)

\(\frac{41}{9}+x-\frac{133}{18}=1\cdot\frac{47}{3}\)

\(\frac{41}{9}+x-\frac{133}{18}=\frac{47}{3}\)

\(\frac{41}{9}+x=\frac{133}{18}+\frac{47}{3}\)

\(\frac{41}{9}+x=\frac{415}{18}\)

               \(x=\frac{415}{18}-\frac{41}{9}\)

                \(x=\frac{37}{2}\)

\(2009-\left(4\frac{5}{9}+x-7\frac{7}{18}\right)\div15\frac{2}{3}=2008\)

\(\left(4\frac{5}{9}+x-7\frac{7}{18}\right)\div15\frac{2}{3}=2009-2008\)

\(\left(-3\frac{3}{18}+x\right)\div15\frac{2}{3}=1\)

\(-3\frac{3}{18}+x=15\frac{2}{3}\)

\(x=15\frac{2}{3}+3\frac{3}{18}\)

\(x=15\frac{12}{18}+3\frac{3}{18}\)

\(x=18\frac{15}{18}\)

exactly 100%

x=17,69444444    

\(\left[\left(35\frac{5}{7}+2\frac{3}{4}\right)-5\frac{5}{7}+\frac{1}{4}\right]:\left(11+x\right)=3\)

\(\left[\left(35\frac{5}{7}-5\frac{5}{7}\right)+2\frac{3}{4}+\frac{1}{4}\right]:\left(11+x\right)=3\)

\(\left[30+3\right]:\left(11+x\right)=3\)

\(33:\left(11+x\right)=3\)
\(11+x=11\)

\(x=0\)

\(\left[\left(35\frac{5}{7}+2\frac{3}{4}\right)-5\frac{5}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)

\(\left[\left(\frac{35\times7+5}{7}+\frac{2\times4+3}{4}\right)-\frac{5\times7+5}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)

\(\left[\left(\frac{250}{7}+\frac{11}{4}\right)-\frac{40}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)

\(\left[\frac{1077}{28}-\frac{167}{28}\right]\div\left(11+x\right)=3\)

\(32,5\div\left(11+x\right)=3\)

\(11+x=32,5\div3\)

\(11+x=\frac{65}{6}\)

\(x=\frac{65}{6}-11=-\frac{1}{6}\)

Ta co:

 \(\left[\left(\frac{29}{25}-x\right).\frac{21}{4}\right]:\left[\left(\frac{95}{9}-\frac{29}{4}\right).\frac{36}{17}\right]=\frac{3}{4}\)

\(\left[\left(\frac{29}{25}-x\right).\frac{21}{4}\right]:\left(\frac{119}{36}.\frac{36}{17}\right)=\frac{3}{4}\)

\(\left[\left(\frac{29}{25}-x\right).\frac{21}{4}\right]:7=\frac{3}{4}\)

\(\left(\frac{29}{25}-x\right).\frac{21}{4}=\frac{3}{4}.7=\frac{21}{4}\)

\(\frac{29}{25}-x=\frac{21}{4}:\frac{21}{4}=1\)

\(x=\frac{29}{25}-1=\frac{4}{25}\)

tập trung sẽ bt làm

mik nhầm nha mn

\(1-\left\{5\frac{4}{9}+x-7\frac{7}{18}\right\}:15\frac{3}{4}=0\)

           Bài làm :

Ta có :

\(...\)

\(\left\{5-\frac{4}{9}+x-7\frac{7}{18}\right\}\div15\frac{3}{4}=1\)

\(5-\frac{4}{9}+x-7\frac{7}{18}=15\frac{3}{4}\)

\(x-\frac{17}{6}=15\frac{3}{4}\)

\(x=15\frac{3}{4}+\frac{17}{6}=\frac{223}{12}\)

Vậy x=223/12

a= (\(\frac{2}{5}\)+\(\frac{2}{9}\)+\(\frac{2}{11}\)\(\times\)\(\frac{5}{7}\)\(+\frac{7}{9}\)\(+\frac{7}{11}\)\()\)