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a) \(\left(x-35\right)-120=0\)
\(\Rightarrow x-35=120\)
\(\Rightarrow x=120+35\)
\(\Rightarrow x=155\)
b) \(124+\left(118-x\right)=217\)
\(\Rightarrow118-x=93\)
\(\Rightarrow x=25\)
c) \(156-\left(x+61\right)=82\)
\(\Rightarrow x+61=74\)
\(\Rightarrow x=13\)
a) ( x - 35 ) - 120 =0
x - 35 = 0 + 120
x - 35 = 120
x = 120 + 35
x = 155
b) 124 + ( 118 - x ) = 217
118 - x = 217 - 124
118 - x = 93
x = 118 - 93
x = 25
c) 156 - ( x + 61 ) = 82
x + 61 = 156 - 82
x + 61 = 74
x = 74 - 61
x = 13
a) 124 + (118 - x) = 217
118 - x = 217 - 124
118 - x = 93
x = 118 - 93
x = 25
b) 156 - (x + 61) = 82
x + 61 = 156 - 82
x + 61 = 74
x = 74 - 61
x = 13
c) 219 - 7(x + 1) = 100
7(x + 1) = 219 - 100
7(x + 1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
d) (3x - 6).3 = 3⁴
3x - 6 = 3⁴ : 3
3x - 6 = 3³
3x - 6 = 27
3x = 27 + 6
3x = 33
x = 33 : 3
x = 11
e) 231 - (x - 6) = 1339 : 13
231 - (x - 6) = 103
x - 6 = 231 - 103
x - 6 = 128
x = 128 + 6
x = 134
a) 124 + (118 - x) = 217
118 - x = 217 - 124
118 - x = 93
x = 118 - 93
x = 25
b) 156 - (x + 61) = 82
x + 61 = 156 - 82
x + 61 = 74
x = 74 - 61
x = 13
c) 219 - 7(x + 1) = 100
7(x + 1) = 219 - 100
7(x + 1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
d) (3x - 6) . 3 = 34
(3x - 6) . 3 = 81
(3x - 6) = 81 : 3
(3x - 6) = 27
3x = 27 + 6
3x = 33
x = 33 : 3
x = 11
e) 231 - (x - 6) = 1339 : 13
231 - (x - 6) = 103
(x - 6) = 231 - 103
x - 6 = 128
x = 128 + 6
x = 134
a. (x-35)-120=0
=> x-35 = 0+120
=> x-35 = 120
=> x = 120+35
=> x = 155
b. 156-(x+61)=82
=> x+61=156-82
=> x+61=74
=> x = 74-61
=> x = 13
c. 124+(118-x)=217
=> 118-x=217-124
=> 118-x=93
=> x = 118-93
=> x = 25
Vận dụng điều lưu ý trong phần tóm tắt kiến thức.
a) Nếu (x - 35) - 120 = 0 thì x - 35 = 120. Do đó x = 120 + 35 = 155.
b) Nếu 124 + (118 - x) = 217 thì 118 - x = 217 - 124 hay 118 - x = 93.
Do đó x = 118 - 93 = 25.
c) 156 - (x + 61) = 82 suy ra x + 61 = 156 - 82 hay x + 61 = 74.
Do đó x = 74 - 61 = 13.
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a) 70 - 5 .(x -3 ) =45
5 . ( x - 3 ) = 70 - 45
5 . ( x - 3 ) = 25
x - 3 = 25 : 5
x - 3 = 5
x = 5 + 3
x = 8
b) 156 - ( x + 61 )+82
sai đề ( không có kết quả )
c) 10 +2 .x = 45 : 43
10 + 2 . x = 42 = 16
2 . x = 16 -10
2 . x = 6
x = 6 : 2
x = 3
d) [(10 - x ).2 +3 ];3 -2=13
[ ( 10 - x ) . 2 + 3 ] : 3 = 13 + 2
[ ( 10 - x ) . 2 + 3 ] : 3 = 15
[ ( 10 - x ) . 2 + 3 ] = 15 x 3
[ ( 10 - x ) . 2 + 3 ] = 45
( 10 - x ) . 2 = 45 - 3
( 10 - x ) . 2 = 42
10 - x = 42 : 2
10 - x = 21
x = 10 - 21
x = - 11
hok tốt
a) x = 25 - 16
x = 9
b) 2x = 156-82
2x = 74
x = 74 : 2
x = 37
c) 150 : (18-x) = 150-125
150 : (18-x) = 25
18-x = 150 : 25
18-x = 6
x =18-6
x= 12
d) 6.6 :x = 8-4
36 : x = 4
x =36:4
x = 9
e)(99x-x) : 2+1= 50x
Ta có:
50x + (1+3+5+7+9+.....+99)=75.10.10
50x + (99+1).50:2 =7500
50x + 2500=7500
50x=7500-2500
50x=5000
x =5000:50
x = 100
Tim x € N biet :
a / x + 16 = 25
=> x = 25 - 16
=> x = 9
b / 156 - 2x = 82
=> 2x = 156 - 82
=> 2x = 74
=> x = 37
c / 150 -150 : ( 18 - x ) = 125
=> 150 : ( 18 - x ) = 125 -150
=> 150 : ( 18 - x ) = - 25
=> 18 - x = -6
=> x = 18 - ( -6 )
=> x = 24
d / 62 : x = 23 - 4
=> 36 : x = 8 - 4
=> 36 : x = 4
=> x = 36 : 4
=> x = 9
e / x + 3x + 5x + ................. +99x = 75 × 102
=> x + 3x + 5x +....+ 99x = 7500
=> x. ( 1 + 3 + 5 +....+ 99 ) = 7500
Số các số hạng là : ( 99 - 1 ) : 2 + 1 = 50
=> Số cặp là : 50 : 2 = 25
Ta có:
x. ( 1 + 3 + 5 +....+ 99 ) = 7500
=> x. [ ( 1 + 99 ) + ( 2 + 98 ) +.... ] = 7500
=> x. 100 .25 =7500
=> x. 2500 = 7500
=> x = 7500 : 2500
=> x = 3
a)
(x-35)-120=0
=>x-35=0+120
=>x-35=120
=>x=120-35
=>x=85
b)
124+(118-x)=217
=>118-x=217-124
=>118-x=93
=>x=118-93
=>x=25
c) 125-(x+61)=82
=>x+61=125-82
=>x+61=43
=>x= 43-61
=>x= -18
a)
(x-35)-120=0
=>x-35=0+120
=>x-35=120
=>x=120-35
=>x=85
b)
124+(118-x)=217
=>118-x=217-124
=>118-x=93
=>x=118-93
=>x=25
c) 125-(x+61)=82
=>x+61=125-82
=>x+61=43
=>x= 43-61
=>x= -18
a/ \(\left(x-35\right)-120=0\)
\(\Leftrightarrow x-35=0+120\)
\(\Leftrightarrow x-35=120\)
\(\Leftrightarrow x=120+35\)
\(\Leftrightarrow x=155\)
Vậy ...
b/ \(124+\left(188-x\right)=217\)
\(\Leftrightarrow188-x=217-124\)
\(\Leftrightarrow188-x=93\)
\(\Leftrightarrow x=95\)
Vậy ...
b/ \(156-\left(x+61\right)=82\)
\(\Leftrightarrow x+61=74\)
\(\Leftrightarrow x=13\)
Vậy ..
a) 2 : (x - 1) = 9
x - 1 = 2 : 9
x - 1 = \(\frac{2}{9}\)
x = \(\frac{2}{9}+1\)
x = \(\frac{11}{9}\)
b) 156 - (x + 61) = 82
x + 61 = 156 - 82
x + 61 = 74
x = 74 - 61
x = 13
c) 13 + (x - 1) = 6
x - 1 = 6 - 13
x - 1 = -7
x = -7 + 1
x = -6
thaks
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