cach lam bai : giup minh voi

tim x thuoc Z biet:

a, /x/+/y/=0

b, /x/ + /y/= 1

tim x : (x+2)/2019 + (x+3)/2018 + (x+4)/2017 + (x+5)/1008 + (x+2076)/11 = 0

lam nhu the nao giup minh voi

a/[x-2][7-x] > 0 . tim x thuoc Z

b/[x mu 2+13][x mu 2-17] > 0  . tim x thuoc Z

c/[x mu 2-13][x mu 2-17] <0  . tim x thuoc Z

GIUP MINH VOI      

NGAY KIA MINH DI BOI DUONG ROI

CAM ON CAC BAN NEU CAC BAB GIUP MINH

Giup mink cau nay nha

1,chung minh dang thuc

-(-a+b+c)+(b-c-1)=(b-c+6)-(7-a+b)+c

2,Tim x thuoc Z

(x+1)+(x+3)+(x+5)+.....+(x+99)=0

(x-3)+(x-2)+(x-1)+...+10+11=0

Lam on giup toi voi: 

tim x thuoc Z:

a, ( x + 1 ) . ( x + 5 )  < 0

Bai 1: Tim so nguyen x biet:

x+(x+1)+(x+2)+...+35=0

Bai 2: Tim GTLN:

a) 8-(x+2)^2=E

b) -|x+2|+10=F

Bai 3: Tim x \(\in\)Z:

a)(2x-4)(x+4)<0

b)(x+5)(3x-12)>0

Bai 11: Cho:

S=1-2+3-4+5-6+...+19-20

a) S co\(⋮\)2; 3; 5 khong?

b) Tim tat ca cac uoc cua S

chi tiet gi minh nha

Tim x biet :

 (x + 1) + (x + 2) + (x + 3 )+ ... + (x + 20) = 250

BAI NAY LA BAI SAO DO CAC BAN MINH KHONG BIET LAM CAC BAN GIUP MINH VOI

Bai 1:

a) Cho A = 963 + 351 + x voi x thuoc N . Tim dieu kien cua x de A chia het cho 9 , de A khong chia hat cho 9

b) Cho B = 10 + 25 + x + 45 voi x thuoc N . Tim dieu kien cua x De B chia het cho 5 , B khong chia het cho 5

Bai 2 : Tim x thuoc N biet :

a) 1 + 2 + 3 + ..... + n = 325

b) 1 + 3 + 5 +... + ( 2n+1) = 144

c) 2 + 4 + 6 + ... + 2n = 756