2346 : (25 + x) = 23

=> 25 + x = 2346 : 23 = 102

=> x = 102 - 25  =  77

Vậy x = 77

2(x-3) + 5(x+4) = 49

=> 2x - 6 + 5x + 20 = 49

=> 7x + (20 - 6) = 49

=> 7x + 14 = 49

=> 7x = 49 - 14 = 35

=> x = 35 : 7 = 5

Vậy x = 5

(2x-10)³ . 25¹⁰⁰⁷ = \(5^2.5^{2015}\)

\(\left(2x-10\right)^3.5^{2014}=5^{2014}.5^3\)

\(\left(2x-10\right)^3=5^3\)

2x - 10 = 5

=> 2x = 5 + 10 = 15

=> x = 15  2 = 7,5

Vậy x = 7,5

1. a. 2346:(25+x)=23

=> 25+x=2346:23

=> 25+x=102

=> x=102-25

=> x=77

b. 2(x-3)+5(x+4)=49

=> 2x-6+5x+20=49

=> 7x+14=49

=> 7x=49-14

=> 7x=35

=> x=35:7

=> x=5

c. (2x-10)³.25¹⁰⁰⁷=5².5²⁰¹⁵

=> (2x-10)³.(5²)¹⁰⁰⁷=5²⁰¹⁷

=> (2x-10)³.5²⁰¹⁴=5²⁰¹⁷

=> (2x-10)³=5²⁰¹⁷:5²⁰¹⁴

=> (2x-10)³=5³

=> 2x-10=5

=> 2x=5+10

=> 2x=15

=> x=15:2

=> x=7,5

Tìm x thuoc z:

1) \(26-\left|x+9\right|=-13\)

\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)

\(\Leftrightarrow\left|x+9\right|=39\)

\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)

Vậy: \(x\in\left\{30;-48\right\}\)

2) \(\left|x+7\right|-13=25\)

\(\Leftrightarrow\left|x+7\right|=25+13=38\)

\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)

\(\Leftrightarrow x\in\left\{31;-45\right\}\)

Vậy:.................

tim x biet

\(1)123-3.\left(x+4\right)=23\)

\(\Leftrightarrow3\left(x+4\right)=123-23\)

\(\Leftrightarrow3\left(x+4\right)=100\)

\(\Leftrightarrow x+4=\frac{100}{3}\)

\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)

Vậy:................

2) Tương tự

1234567

a) <=> 15-5x-20=-12-3

<=> -5x=-12-3-15+20=-10

=>x=-10:(-5)=2

b)<=>7-x-25-7=-25

<=> -x=-25-7+25+7=0 =>x=0

c) /x+2/=0 => x+2=0 =>x=-2

d) sai đề

e)<=> /x-5/ = 7

<=> \(\orbr{\begin{cases}x-5=7\\x-5=-7\end{cases}}\)

<=> \(\orbr{\begin{cases}x=12\\x=-2\end{cases}}\)

g) <=> -x-20-8+2x=-15

<=> x=-15+20+8=13

d là | x + 3 | = 7 - ( - 2 )

(-25)-(5.x-3)=4

5.x-3 = -25 - 4

5.x-3=-29

5.x=-26

x=-26/5

x=-5,2

5.x-6=20-(12-6)

5.x-6=20-6

5.x-6=14

5.x=20

x=20:5

x=4

vậy x=4

XÝ a mik ko hiểu

b) x-5²=-4

x-25=-4

x=-4+25

x=21
c) x+3³=2³

^{x-27=8
x=8+27}

^x=35

^{d) \(|x-7|+9=-3\)}

\(|x-7|=\left(-3\right)+9\)

\(|x-7|=6\)

\(|x|=6+7\)

\(\Rightarrow x=13\)hoặc \(x=-13\)

Thoi chán òi hổng lèm nửa âu~~

Trả lời :

Làm tiếp nha :)

e ) | 5 - x | - 7 = -3

 \(=>\) \(\left|5-x\right|\) \(=\) \(-3+7\) \(=\) \(4\)

\(=>\) \(\orbr{\begin{cases}5-x=4\\5-x=-4\end{cases}}\)\(=>\) \(\orbr{\begin{cases}x=5-4\\x=5-\left(-4\right)\end{cases}}\)\(=>\) \(\orbr{\begin{cases}x=1\\x=9\end{cases}}\)

g ) 4^x : 2 = 32

<=> 4^x = 32 x 2

<=> 4^x = 64

<=> 4^x = 4³

=> x = 3

h ) mk chưa hiểu lắm ^^

k ) x¹⁰ = x⁸ => x = 0 hoặc 1 ( mk nghĩ vậy )

_Vì 0¹⁰ = 0⁸ ; 1¹⁰ = 1⁸

_Học tốt nhea

`#040911`

`a)`

`6 \times x - 5 = 613`

`=> 6 \times x = 613 + 5`

`=> 6 \times x = 618`

`=> x = 618 \div 6`

`=> x = 103`

Vậy, `x = 103`

`b)`

`12 \times x + 3 \times x = 30`

`=> x \times (12 + 3) = 30`

`=> x \times 15 = 30`

`=> x = 30 \div 15`

`=> x = 2`

Vậy, `x = 2`

`c)`

`125 - 25 \times (x - 1) = 100`

`=> 25 \times (x - 1) = 125 - 100`

`=> 25 \times (x - 1) = 25`

`=> x - 1 = 25 \div 25`

`=> x - 1 = 1`

`=> x = 1 + 1`

`=> x = 2`

Vậy, `x = 2`

`d)`

`(x - 2) \times (9x - 4) = 0?`

`=>`

TH1: `x - 2 = 0`

`=> x = 0 + 2`

`=> x = 2`

TH2: `9x - 4 = 0`

`=> 9x = 4`

`=> x = 4/9`

Vậy, `x \in {2; 4/9}.`

\(a,6x-5=613\\ \Leftrightarrow6x=618\\ \Leftrightarrow x=103\\ b,12x+3x=30\\ \Leftrightarrow15x=30\\ \Leftrightarrow x=2\\ c,125-25\left(x-1\right)=100\\ \Leftrightarrow25\left(x-1\right)=25\\ \Leftrightarrow x-1=1\\ \Leftrightarrow x=2\\ d,\left(x-2\right)\cdot\left(9x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{4}{9}\end{matrix}\right.\)