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\(\frac{x}{2}=\frac{x-8}{10}\)
\(\frac{5x}{10}=\frac{8}{10}\)
=>5x=8
=>x=\(\frac{8}{5}\)
\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)\cdot.....\cdot\left(1-\frac{1}{2020}\right)\)
\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot.....\cdot\frac{2019}{2020}\)
\(=\frac{1\cdot2\cdot3\cdot.....\cdot2019}{2\cdot3\cdot4\cdot....\cdot2020}=\frac{1}{2020}\)
a) 32x = 81= 34
=> 2x = 4
x = 2
b) 52x-3 - 2.52 = 52.3
52x-3 = 125 = 53
=> 2x - 3 = 3
=> 2x = 6
x = 3
\(x^{2020}=x\Leftrightarrow x^{2020}-x=0\Leftrightarrow x\left(x^{2019}-1\right)=0\Leftrightarrow\orbr{\begin{cases}x=0\\x^{2019}-1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x^{2019}=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
\(1+2+2^2+2^3+....+2^{2019}+2^{2020}\)
\(A=\left(1+2+2^2\right)+\left(2^3+2^4+2^5\right)+....+\left(2^{2016}+2^{2017}+2^{2018}\right)+2^{2019}+2^{2020}\)
\(A=\left(1+2+2^2\right)+2^3\left(1+2+2^2\right)+.....+2^{2016}\left(1+2+2^2\right)+2^{2019}+2^{2020}\)
\(A=7+2^3.7+2^6.7+2^9.7+....+2^{2016}.7+2^{2019}+2^{2020}\)
\(\text{Ta có:}2^{2019}+2^{2020}=8^{673}+8^{673}.2\equiv1+1.2\left(\text{mod 7}\right)\equiv3\left(\text{mod 7}\right)\Rightarrow A\text{ chia 7 dư 3}\)
30 - (x + 2) = 14
(x + 2) = 30 - 14
x + 2 = 16
x = 16 - 2
x = 14
2018 x ( 2017 - x ) = 0
(2017 - x) = 0 : 2018
2017 - x = 0
x = 0 + 2017
x = 2017
720 : { 41 - ( 2x - 5 ) } = 40
{ 41 - ( 2x - 5 ) } = 720 : 40
{ 41 - ( 2x - 5 ) } = 18
( 2x - 5 ) = 18 + 41
( 2x - 5 ) = 59
2x = 59 + 5
2x = 64
x = 64 : 2
x = 32
(x + 1) ( x+2 ) (x+3) + ....+ ( x+100 ) = 5750
(x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 5750
(x .100) + (1+100) . 100 : 2 = 5750
(x.100) + 5050 = 5750
x.100 = 5750 - 5050
x . 100 = 700
x = 700 : 100
x =7
a. 30 - (x + 2) = 14
x + 2 = 30 - 14
x = 16 - 2
x = 14
b. 2018 . (2017 - x) = 0
2017 - x = 0 : 2018
x = 2017 - 0
x = 2017
c. 720 : [41 - (2x - 5)] = 40
41 - (2x - 5) = 720 : 40
2x - 5 = 41 - 18
2x = 23 + 5
x = 28 : 2
x = 14
d. (x + 1) (x + 2) (x + 3) + ... + (x + 100) = 5750
(x + x +...+ x + x) (1 + 2 + 3 + ... + 100) = 5750
100x + [(1 + 100) . 100 : 2 ] = 5750
100x + 5050 = 5750
100x = 5750 - 5050
x = 700 : 100
x = 7
X . 40%=2020 : 2 . 5+2/5
X = 5050
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