Bài 6:

\(21,251+6,058+0,749+1,042\)

\(=\left(21,251+0,749\right)+\left(6,058+1,042\right)\)

\(=22+7,1\)

\(=29,1\)

___________________

\(1,53+5,309+12,47+5,691\)

\(=\left(1,53+12,47\right)+\left(5,309+5,691\right)\)

\(=14+11\)

\(=25\)

5:

a: =>x/17=5/17

=>x=5

b; =>6+x=7/11*33=21

=>x=15

c: \(\dfrac{12+x}{43-x}=\dfrac{2}{3}\)

=>3x+36=86-2x

=>5x=50

=>x=10

d: \(\dfrac{x}{5}< \dfrac{3}{7}\)

=>x<3/7*5

=>x<15/7

f: 15/26+x/16=46/52

=>x/16=23/26-15/26=8/26=4/13

=>x=4/13*16=64/13

a; -2\(x\) - 3.(\(x-17\)) = 34 - 2.( - \(x\) + 25)

    - 2\(x\) - 3\(x\) + 51 = 34 + 2\(x\) - 50

       2\(x\) + 2\(x\) + 3\(x\) = - 34 + 50 + 51

            7\(x\)            = 67

               \(x\)           =  67 : 7

                \(x\)         =  \(\dfrac{67}{7}\)

Vậy \(x\) = \(\dfrac{67}{7}\) 

b; 17\(x\) + 3.(- 16\(x\) - 37) = 2\(x\) + 43 - 4\(x\)

    17\(x\) - 48\(x\)  - 111 =  2\(x\) - 4\(x\) + 43

    - 31\(x\) - 2\(x\) + 4\(x\) = 111 + 43

        - \(x\) x (31 + 2 - 4) = 154

        - \(x\) x (33 - 4) =  154

         - \(x\) x 29 = 154

         - \(x\)         = 154 : (-29)

           \(x\)        = - \(\dfrac{154}{29}\)

          Vậy \(x=-\dfrac{154}{29}\) 

\(2x-5=-11\Leftrightarrow x=-3\)

\(\text{1/ (2x - 5) +17 =6}\\ 2x-5=6-17\\ 2x-5=-11\\ 2x=-11+5\\ x=-6:2\\ x=-3\)

nhân ra r chuyển vế là xong mà

giúp mình 1 câu

a: \(x+7⋮x+2\)

=>\(x+2+5⋮x+2\)

=>\(5⋮x+2\)

=>\(x+2\in\left\{1;-1;5;-5\right\}\)

=>\(x\in\left\{-1;-3;3;-7\right\}\)

b: \(2x+5⋮x+1\)

=>\(2x+2+3⋮x+1\)

=>\(3⋮x+1\)

=>\(x+1\in\left\{1;-1;3;-3\right\}\)

=>\(x\in\left\{0;-2;2;-4\right\}\)

c: \(3x-2⋮x+3\)

=>\(3x+9-11⋮x+3\)

=>\(-11⋮x+3\)

=>\(x+3\in\left\{1;-1;11;-11\right\}\)

=>\(x\in\left\{-2;-4;8;-14\right\}\)

d: \(12x+1⋮3x+2\)

=>\(12x+8-7⋮3x+2\)

=>\(-7⋮3x+2\)

=>\(3x+2\in\left\{1;-1;7;-7\right\}\)

=>\(3x\in\left\{-1;-3;5;-9\right\}\)

=>\(x\in\left\{-\dfrac{1}{3};-1;\dfrac{5}{3};-3\right\}\)

e: \(x^2+3x+5⋮x+3\)

=>\(x\left(x+3\right)+5⋮x+3\)

=>\(5⋮x+3\)

=>\(x+3\in\left\{1;-1;5;-5\right\}\)

=>\(x\in\left\{-2;-4;2;-8\right\}\)

f: \(x^2-2x+3⋮x+2\)

=>\(x^2+2x-4x-8+11⋮x+2\)

=>\(11⋮x+2\)

=>\(x+2\in\left\{1;-1;11;-11\right\}\)

=>\(x\in\left\{-1;-3;9;-13\right\}\)

giúp mik với

tìm số ngyên x :

a) -2x-(x-17)=34-(-x+25)
-2x - x +17 =34 + x -25
-3x + 17 =9 +x
-3x + 17 - 9 -x=0
-4x + 8 = 0
-4x = -8
x =2 

giúp mk nhé mọi người cảm ơn mọi người nhìu nha

Bài này khó quá , mk ko bít !!!